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Komok [63]
3 years ago
7

Bruno has 8 book shelves. Each shelf can hold 9 books. How many books fit on all 8 shelves? A) 56 books B) 60 books C) 63 books

D) 72 books
Mathematics
1 answer:
Lady_Fox [76]3 years ago
8 0

Answer:

D) 72 is correct because 8 times 9 is 72! Hope this helped. :)

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I really need help with this Triangle problem. ​
dedylja [7]

Answer:

12

Step-by-step explanation:

Here we use SOHCAHTOA

Seeing as we have the hypotenuse and we are working to find out the opposite, we use SOH

Sin(x)= Opposite/Hypotenuse

Sin(45) = x/12\sqrt{2} \\

×12 root 2

sin(45) times 12 root 2=  12

x=12

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3 years ago
A transcriptionist types 62 words per minute. Which statement is correct? As the number of words increases, the number of minute
Monica [59]

Answer:

The number of words, w, is the dependent variable.

Step-by-step explanation:

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3 years ago
Helpmepleaseeeeeeee<br> 1.
Vedmedyk [2.9K]
1. <span><span>7 2/9</span>−<span>4 <span>2/3</span></span></span><span>=<span>2 <span>5/9</span></span></span><span>(Decimal: 2.555556)</span>
4 0
3 years ago
Read 2 more answers
Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex
bagirrra123 [75]

Answer:

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

\hat p=0.021 estimated proportion of interest

p_o=0.012 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:  

Null hypothesis:p \leq 0.012  

Alternative hypothesis:p > 0.012  

When we conduct a proportion test we need to use the z statisitic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0
3 years ago
Each bucket holds 212
serg [7]

Answer:

5088

Step-by-step explanation:

212*24=5088

5 0
3 years ago
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