Note that h(x) = 4x^2 - 8x - 60 factors to 4(x^2 - 2x - 15), and that the roots (zeros) of (x^2 - 2x - 15) are -5 and +3. Thus, the smallest zero is -5.

3 0

4 years ago

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AHHHHHHHHHHHHHHH SOMEONE ANSWEER THIS PLEEASEEE NEED ANSWER ASP 20 pts!! Please answer!!! I literally don't get this ;c so PLEAS

Blababa [14]

Answer:

$P(A\textrm{ and }B)=\frac{3}{14}$

Step-by-step explanation:

Given:

$P(A)=\frac{4}{7}$

$P(B|A)=\frac{3}{8}$

We know that, conditional probability of B given that A has occurred is given as:

$P(B|A)=\frac{P(A\cap B}{P(A)}$ . Expressing this in terms of $P(A\cap B)$ , we get

$P(A\cap B)=P(B|A)\times P(A)$

Plug in the known values and solve for $P(A\cap B)$ . This gives,

$P(A\cap B)=P(B|A)\times P(A)\\P(A\cap B)=\frac{3}{8}\times \frac{4}{7}\\P(A\cap B)=\frac{12}{56}=\frac{3}{14}$

Therefore, the probability of events A and B occurring is $\frac{3}{14}$ .

6 0

3 years ago

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