-9.5 because 1/2 simplifies to .5 and 9 is the whole number
Answer:
0.27 repeating.
Step-by-step explanation:
So to solve this we just have to use division.
1 clearly doesnt go into 3 at least one time, so we can add a decimal point and add a 0 to make it 30.
11 goes into 30 2 times, so we have:
0.2
and 30-22=8
So we can add another 0 and make it 80.
Then 11 goes into 80 7 times. So we have:
0.27
and 80-77=3
So again, add the 0, we have 30.
11 goes into 30 2 times, so:
0.272
and 30-22=8
Add another 0 we get 80.
11 goes into 80 7 times.
So finally, we have:
0.2727.
This is a repeating decimal.
This can be shown as:
0.<u>27</u>
So this is your answer!
I was a bit confused with which one it was on your answer key, but knowing that it is 0.<u>27</u> I am guessing you can chose!
Hope this helps!
Answer:
Step-by-step explanation:
Solve the value of 
:
-Combine 
and 
by subtracting by :
-Subtract 
on both sides:
-Multiply both sides by 
, the reciprocal of 
:
Therefore, the value of is 
.
Answer:
y=1x-4
Step-by-step explanation:
The original is
y=mx+b
m is the slope and b is the y intercept
Answer:
g(-4) = -1
g(-1) = -1
g(1) = 3
Explanation:
If you are given a function that is defined by a system of equations associated with certain intervals of x, just find which interval makes x true, and then substitute x into the equation of that interval.
For example, given g(-4), this is an expression which is asking for the value of the equation when x = -4. So -4 is not ≥ 2, so ¼x - 1 will not be used. -4 is also not ≤ -1 and ≤ 2, so -(x - 1)² + 3 will not be used either. So in turn, we will just use -1 which is always -1 so g(-4) will just be -1, right because there is no x variable in -1 so it will always be the same.
Using the same idea as before g(-1) is g(x) when x = -1 so -1 will not be a solution because -1 is not less than -1 (< -1). -1 is not ≥ 2 either so we will be using the second equation because -1 is part of the interval -1≤x≤2 (it is a solution to this inequality), therefore -(x - 1)² + 3 will be used.
As x = -1, -(x - 1)² + 3 = -(-1 - 1)² + 3 = -(-2)² + 3 = -4 + 3 = -1.
It is a coincidence that g(-1) = -1.
Now for g(1), where g(x) has an input of 1 or the value of the function where x = 1, we will not use the first equation because x = 1 → x < -1 → 1 < -1 [this is false because 1 is never less than -1], so we will not use -1.
We will use -(x - 1)² + 3 again because 1 is not ≥ 2, 1≥2 [this is also false]. And -1 ≤ 1 < 2 [This is a true statement]. Therefore g(1) = -(1 - 1)² + 3 = -(0)² + 3 = 3
