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Alexus [3.1K]
3 years ago
6

How to find length of the flower bed, divide the area by the width

Mathematics
2 answers:
Zigmanuir [339]3 years ago
7 0
Area = length x width

with a little algebra we can reorganize the equation and solve for length...

A = L x W
A/W = L

So the statement divide the area by the width is TRUE.
Verizon [17]3 years ago
6 0
As we know,
Area = length × width

Divide width on both sides

Area/width = length × width/ width

Flip the equation
Length = Area/width

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= Knowledge Check Carmen gave $1.39 to one friend and $2.31 to another friend. Find the total amount Carmen gave to the two frie
Anna71 [15]

Answer:

3.71

Step-by-step explanation:

Add the money.....

8 0
3 years ago
And I'm stuck again ahahah.
IceJOKER [234]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Angle XBC = 55 degrees because corresponding angles are equal

b) We already know angle XBC

Angle XCB = Angle XBC because isosceles base angles are equal

Therefore, angle XCB = 55 degrees

Angles in a triangle equal 180 degrees

180 - (55 + 55) = 70

Angle BXC = 70 degrees

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6 0
3 years ago
Read 2 more answers
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
Who knows the answer to this ?
Iteru [2.4K]

Answer:

D

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
a metal strip is being installed around a workbench that is 6 feet long and 2 feet wide. find how much stripping is needed
Stolb23 [73]
Given that the metal strip is being installed around a bench that 6ft long 2ft wide. The metal required will be given by:
P=4(L+W)
=4(6+2)
=4(8)
=32 ft
Therefore we conclude that we need a metal strip that is 32ft long
4 0
3 years ago
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