First of all, we compute the points of interest, i.e. the points where the curve cuts the x axis: since the expression is already factored, we have

Which means that the roots are
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Next, we can expand the function definition:

In this form, it is much easier to compute the derivative:

If we evaluate the derivative in the points of interest, we have

This means that we are looking for the equations of three lines, of which we know a point and the slope. The equation

is what we need. The three lines are:
This is the tangent at x = -2
This is the tangent at x = 0
This is the tangent at x = 1
Descending order...largest to smallest
the largest one is the one with the biggest exponent
so the first term is : 7z^4
Answer:
Step-by-step explanation:
The significant figures of a number that carry meaningful contribution to its measurement resolution
Answer:
k > -26
Step-by-step explanation:
To isolate the k, you subtract 6 from both sides to get k < -26.
Step-by-step explanation:
domain is the valid interval for the x (input) values for the function.
the range is the valid interval for the y (result) values of the function.
so, we have a function definition and a valid domain interval for x. we therefore try the x values and see what result values they create. and that defines the range.
x = -6
y = 4 - -6 = 4 + 6 = +10
c
x = 2
y = 4 - 2 = +2
x = 7
y = 4 - 7 = -3
we have therefore a range of {-3, 2, 10}