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notsponge [240]
3 years ago
8

60 peoples will be attending a dinner party. each people at the party can seat 8 people. how many tables are needed? Write and s

olve the number fact you used to find the answer, and explain your reasoning
Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
8 0
The answer is 480 because u need to multiply 60 and 8 together
Gnoma [55]3 years ago
3 0
The answer is 7.5
But u need 8 tables because you cant cut a table in half. The number facts that i used was 60 divided by 8.

PS. Please like this answer or i wont answer anymore of your questions
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What is the domain of the function for this situation?
raketka [301]

Answer:

There is no problem. If you put the problem then i'll help

Step-by-step explanation:

8 0
3 years ago
I need help please ^^
Vaselesa [24]

Answer:

  see below

Step-by-step explanation:

Usually, we're concerned about the relationship of y to x. Here, the question is asking you to consider the relationship of x to y.

The easiest way to find the answer to this one is to check the given explanations to see which is true. You can pretty much ignore the first row of the table and just look at the second row where x=5 and y=15.

  • it is NOT TRUE that x is 3 times y (5 is not 3 times 15)
  • it is TRUE that x is 1/3 of y (5 is 1/3 of 15)
  • it is NOT TRUE that x is 5 times y (5 is not 5 times 15)
  • it is NOT TRUE that x is 1/5 of y (5 is not 1/5 of 15)

_____

If you know your multiplication tables, you know that 15 = 3×5, so ...

  5 = 15/3

  5 = (1/3) × 15

The relationship of these numbers should not be a mystery.

4 0
3 years ago
HELP WITH THESE QUESTIONS PART 2.
polet [3.4K]

Answer: (a) IV (b) positive (c) \frac{\pi}{4} (d) C (e) \sqrt{2}

<u>Step-by-step explanation:</u>

a) \frac{15\pi}{4} - \frac{8\pi}{4} = \frac{7\pi}{4}, which is located in Quadrant IV <em>per the Unit Circle.  </em>

b) sec is \frac{1}{cos}. Cos is the x-coordinate.  The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from \frac{7\pi}{4} to 2π = \frac{\pi}{4}

d) since the angle is below the x-axis and the reference angle is\frac{\pi}{4}, then the angle is equal to -sec(\frac{\pi}{4})

e) sec = \frac{1}{cos}   ⇒   sec \frac{7\pi}{4} = \frac{2}{\sqrt{2} } = \frac{2}{\sqrt{2} }(\frac{\sqrt{2}} {\sqrt{2}}) = \frac{2\sqrt{2} }{2} = \sqrt{2}

**********************************************************

Answer: (a) \frac{3\pi}{2} (b) (0, -1) (c) A (d) -1

<u>Step-by-step explanation:</u>

a) \frac{11\pi}{2} - \frac{4\pi}{2} = \frac{7\pi}{2} - \frac{11\pi}{2} = \frac{3\pi}{2}

b) \frac{3\pi}{2} is on the Unit Circle at (0, -1)

c) sin = \frac{opposite}{hypotenuse} which equals \frac{y}{r} on the Unit Circle.

d) sin is the y-coordinate. sin (\frac{3\pi}{2}) = -1

6 0
3 years ago
A) What is the lower quartile of the data represented in the following box-and-whisker plot?
vovikov84 [41]
The lower quartile is 24 and the range is 35-22=13.....hope this helps
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Compare the rates to find which is the best value.
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6 greeting cards for 23.40

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