Answer:
one solution
Step-by-step explanation:
Shifts the graph left 2, would look like
(x+2)^2
Answer:

Step-by-step explanation:
Work done is given by
, where d = length of cable and w = weight of cable.
Here, d = 175 ft and w = 3 lb/ft
Now, 
![work \ done= 3\left [175x-\frac{x^2}{2} \right ]_0^{175}](https://tex.z-dn.net/?f=work%20%5C%20done%3D%203%5Cleft%20%5B175x-%5Cfrac%7Bx%5E2%7D%7B2%7D%20%20%5Cright%20%5D_0%5E%7B175%7D)
![work \ done= 3\left [175^2-\frac{175^2}{2} \right ]](https://tex.z-dn.net/?f=work%20%5C%20done%3D%203%5Cleft%20%5B175%5E2-%5Cfrac%7B175%5E2%7D%7B2%7D%20%20%5Cright%20%5D)


Discount of 5
6% tax
100-5=95
100+6=106
12*0.95*1.06=12.084
the price is $12.08
Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.