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Pavel [41]
3 years ago
13

What is the solution

Mathematics
1 answer:
In-s [12.5K]3 years ago
4 0
The solution that makes both equations true is 'a', or (2,0), because if you substitute the 2 with the x and the 0 with the y, and solve both equations, you get the same answer. Also, you could try a graphing software, like desmos.
0=-2(2)+4
-4+4
0=0
0=(2)-2
0=0
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What is the sum of the first 30 terms of this arithmetic sequence? 6,13,20,27,34
Galina-37 [17]

Answer:

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Step-by-step explanation:

Givens

a1 = 6

Use t4 - t3 to get d

t4 = 27

t3 = 20

Step One

Find a1 and d

a1 = 6

d = t4 - t3

d = 27 - 20

d = 7

Step Two

Find the 30th Term

tn= a1 + (n -1 )*d

t30 = 6 + (30 - 1) * 7

t30 = 6 + 29*7

t30 = 6 + 203

t30 = 209

Step Three

Find the sum using Sum = (a + t30)*n/2

n = 30              given

a1 = 6               given  

t30 = 209         calculated from step 2

Sum = (a1 + t30)*n/2        Substitute

Sum = (6+ 209)*30/2       Combine like terms and divide by 2

sum = 215 * 15                  Multiply

Sum = 3135                      Answer

4 0
3 years ago
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