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Pavel [41]
3 years ago
13

What is the solution

Mathematics
1 answer:
In-s [12.5K]3 years ago
4 0
The solution that makes both equations true is 'a', or (2,0), because if you substitute the 2 with the x and the 0 with the y, and solve both equations, you get the same answer. Also, you could try a graphing software, like desmos.
0=-2(2)+4
-4+4
0=0
0=(2)-2
0=0
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In parallelogram ABCD below, AC is a diagonal, the
Vinil7 [7]

Step-by-step explanation:

  • ABCD parallellogram
  • m< B = m< D = 40
  • in triangle ACD :

m < CAD = 180 - ( 40 + 57 ) = 83

7 0
3 years ago
A rectangle has a length of 0.4m and a width of 5cm less than its length.what is the perimeter of the rectangle
Sliva [168]

Answer:

150cm

Step-by-step explanation:

0.4*100-5=35

(35+40)*2=150

6 0
3 years ago
The sum of three consecutive numbers is 46. Find the
Citrus2011 [14]

Let the three consecutive number be x,x+1 and x+2.

It is given sum of three consecutive numbers is 46.

So,x+x+1+x+2=46

3x+3=46.

Subtracting 3 both sides

3x=46-3

3x=43.

x= \frac{43}{3}.

Since \frac{43}{3}. is not an integer there is no true answer to this problem.


6 0
3 years ago
Read 2 more answers
A rectangle is 20 meters long and 20 meters wide. If the length is increased by 10% and the width is decreased by 10%, what is t
Solnce55 [7]

Consider that the initial length and width of the rectangle are given as,

\begin{gathered} l=20 \\ b=20 \end{gathered}

After the length is increased by 10%, the new length (L) of the rectangle is calculated as,

\begin{gathered} L=(1+\frac{10}{100})\cdot l \\ L=(\frac{110}{100})\cdot20 \\ L=22 \end{gathered}

After the width is decreased by 10%, the new width (B) of the rectangle is calculated as,

\begin{gathered} B=(1-\frac{10}{100})\cdot b \\ B=(\frac{90}{100})\cdot20 \\ B=18 \end{gathered}

Then the area (A) of the new rectangle is calculated as,

\begin{gathered} A=L\times B \\ A=22\times18 \\ A=396 \end{gathered}

Thus, the new area of the rectangle is 396 square meters.

7 0
1 year ago
Evaluate the integral using integration by parts with the indicated choices of u and dv. (Use C for the constant of integration.
trasher [3.6K]

Answer:

\frac{xe^{7x}}{7} + \frac{e^{7x}}{49}

Step-by-step explanation:

Given the integral equation

\int\limits{xe^{7x}} \, dx \\

According to integration by part;

\int\limits {u} \, dv = uv +  \int\limits {v} \, du

u = x, dv = e^7x

du/dx = 1

du = dx

v = \int\limits {e^{7x}} \, dx \\v = e^7x/7

Substitute the given values into the formula;

\int\limits {xe^{7x}} \, dx = x(e^{7x}/7) + \int\limits ({e^{7x}/7}) \, dx\\\int\limits {xe^{7x}} \, dx = \frac{xe^{7x}}{7} + \frac{e^{7x}}{7*7} \\\int\limits {xe^{7x}} \, dx = \frac{xe^{7x}}{7} + \frac{e^{7x}}{49}

3 0
3 years ago
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