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tester [92]
3 years ago
11

Maya has 120 caramel apples to sell. Each caramel apple is covered with one toppin.

Mathematics
1 answer:
EleoNora [17]3 years ago
5 0

they got sold by her

Step-by-step explanation:

lol she sold her apples to people

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To the nearest dollar, what does the analyst believe
ruslelena [56]

The analyst believes the value of the stock at the end of three weeks will be $134.

<h3>What are stocks?</h3>
  • Stock (also known as capital stock) in finance refers to the shares of ownership in a corporation or company.
  • A single share of stock represents fractional ownership of the corporation based on the total number of shares.
  • This typically entitles the shareholder (stockholder) to that fraction of the company's earnings, proceeds from asset liquidation (after discharge of all senior claims such as secured and unsecured debt),  or voting power, which are often divided in proportion to the amount of money invested by each stockholder.

To find the value of the stock:

  • Because the stock price drops by 28% every week, it will be:
  • 100 - 28 = 72% every week.
  • So, r = 0.72.
  • Then, the equation V = 360(r)∧t will be V = 360(0.72)∧t .
  • After 3 weeks, V = 360(0.72)³ = 134.47 = 134

Therefore, the analyst believes the value of the stock at the end of three weeks will be $134.

Know more about stocks here:

brainly.com/question/690070

#SPJ4

The correct question is given below:

To the nearest dollar, what does the analyst believe the value of the stock will be at the end of three weeks? (Note: Disregard the $ sign when gridding your answer.)

3 0
2 years ago
Estimate of 0.75 divided by 3.15
Ganezh [65]
0.3333333333333333333
4 0
3 years ago
Neal opened a savings account 11 years ago with a deposit of $2,335.69. The account has an interest rate of 4.3% compounded dail
Vinvika [58]

Answer: $1,412.52

Step-by-step explanation:

Formula to calculate the accumulated amount if <em>P</em> principal invested for <em>t </em>years at a rate of interest <em>r</em> that compounded daily is given by:-

A=P(1+\dfrac{r}{365})^{365t}

Given: P= $2,335.69

r= 4.3%= 0.043

t= 11 years

Then,

A=2335.69(1+\dfrac{0.043}{365})^{365\times11}\\\\=2335.69(1+0.000117808219178)^{4015}\\\\=2335.69(1.000117808219178)^{4015}\\\\= 2335.69(1.6047566747)\\\\=3748.09044309\approx3748.21\\\\\Rightarrow\ A=\$3748.21

Interest earned = A-P

= $3748.21- 2335.69.

= $1412.52

Hence, Neal earned $1,412.52 as interest.

8 0
3 years ago
find the spectral radius of A. Is this a convergent matrix? Justify your answer. Find the limit x=lim x^(k) of vector iteration
Natasha_Volkova [10]

Answer:

The solution to this question can be defined as follows:

Step-by-step explanation:

Please find the complete question in the attached file.

A = \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right]

now for given values:

\left[\begin{array}{ccc} \frac{3}{4} - \lambda & \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2} - \lambda & 0\\ -\frac{1}{4}& -\frac{1}{4} & 0 -\lambda \end{array}\right]=0 \\\\

\to  (\frac{3}{4} - \lambda ) [-\lambda (\frac{1}{2} - \lambda ) -0] - 0 - \frac{1}{4}[0- \frac{1}{2} (\frac{1}{2} - \lambda )] =0 \\\\\to  (\frac{3}{4} - \lambda ) [(\frac{\lambda}{2} + \lambda^2 )] - \frac{1}{4}[\frac{\lambda}{2} -  \frac{1}{4}] =0 \\\\\to  (\frac{3}{8}\lambda + \frac{3}{4} \lambda^2 - \frac{\lambda^2}{2} - \lambda^3 - \frac{\lambda}{8} + \frac{1}{16}=0 \\\\\to (\lambda - \frac{1}{2}) (\lambda -\frac{1}{4}) (\lambda - \frac{1}{2}) =0\\\\

\to \lambda_1=\lambda_2 =\frac{1}{2}\\\\\to \lambda_3 = \frac{1}{4} \\\\\to A = max {|\lambda_1| , |\lambda_2|, |\lambda_3|}\\\\

       = max{\frac{1}{2}, \frac{1}{2}, \frac{1}{4}}\\\\= \frac{1}{2}\\\\(A) =\frac{1}{2}

In point b:

Its  

spectral radius is less than 1 hence matrix is convergent.

In point c:

\to c^{(k+1)} = A x^{k}+C \\\\\to x(0) =   \left(\begin{array}{c}3&1&2\end{array}\right)  , c = \left(\begin{array}{c}2&2&4\end{array}\right)\\\\  \to x^{(k+1)} =  \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right] x^k + \left[\begin{array}{c}2&2&4\end{array}\right]  \\\\

after solving the value the answer is

:

\lim_{k \to \infty} x^k=o  = \left[\begin{array}{c}0&0&0\end{array}\right]

4 0
3 years ago
What is the answer to this somebody!!!
Fed [463]

Use the geometric mean for right triangles as the sides are related to the hypotenuse. 30 - 6 = 24. We need that for our proportion. \frac{24}{x}=\frac{x}{30}. We cross-multiply to get x^2=720. Taking the square root of both sides gives us that x=12\sqrt{5}, the second choice above.

7 0
3 years ago
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