Answer:
After population (A) = 62,902 (Approx)
Step-by-step explanation:
Given:
Current population (P) = 19613
Number of years (n) = 2020 - 2000 = 20 year
Rate of growth (r) = 6% = 0.06
Find:
After population (A)
Computation:
![After\ population (A) = Current\ population (P)[1+r]^n \\\\After\ population (A) = 19613[1+0.06]^{20} \\\\After\ population (A) = 19613[1.06]^{20} \\\\After\ population (A) = 62,901.548](https://tex.z-dn.net/?f=After%5C%20population%20%28A%29%20%3D%20Current%5C%20population%20%28P%29%5B1%2Br%5D%5En%20%5C%5C%5C%5CAfter%5C%20population%20%28A%29%20%3D%2019613%5B1%2B0.06%5D%5E%7B20%7D%20%5C%5C%5C%5CAfter%5C%20population%20%28A%29%20%3D%2019613%5B1.06%5D%5E%7B20%7D%20%5C%5C%5C%5CAfter%5C%20population%20%28A%29%20%3D%2062%2C901.548)
Answer:
The absolute minimum value is "
" and the absolute maximum value is "
".
Step-by-step explanation:
Given:

on,
![[0,5]](https://tex.z-dn.net/?f=%5B0%2C5%5D)
By differentiating it, we get
⇒ 
Set 
then,
⇒ 

(Critical point)
When x=0,
⇒ 
When
,
⇒
(Absolute minimum)
When 
⇒
(Absolute maximum)
Answer:
4(-9)= -36
Step-by-step explanation:
Since there's a negative on the 9 it will affect the product. So the answer is supposed to be a - 36.
120 IS THE CORRECT ANSWER. BUT THIS IS NOT FOR SURE!
1050.28 Kerry’s money (10years later)
1364.56 Kerry’s money(20years later)
1159.4 Andy’s money (10years later)
1636.8 Andy’s money(20 years later)