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sweet-ann [11.9K]
2 years ago
5

The area of the base of a triangular pyramid with faces that are equilateral triangles is 64 ft squared. Can you find the surfac

e area of the​ pyramid? Explain. Here are the choices
A. No, because the area of the base of a pyramid is not related to the area of its​ faces, so the surface area cannot be found without more information.

b. No, because the base of a pyramid with equilateral triangle faces does not necessarily have the same area as its equilateral faces.

C.Yes, because the area of the base of a triangular pyramid with equilateral triangles for faces is the same as the area of each face.

D.Yes, because the area of the base will be the edge length of each​ face, which can be used to find the area of each face
Mathematics
1 answer:
tankabanditka [31]2 years ago
7 0

Answer:

C.

Step-by-step explanation:

Yes, because the area of the base of a triangular pyramid with equilateral triangles for faces is the same as the area of each face.

So the surface area is 64 * 4 which is 256

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What are the roots of f(x) = x2 – 48? –48 and 48 –24 and 24 Negative 8 StartRoot 3 EndRoot and 8 StartRoot 3 EndRoot Negative 4
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Answer:

x=4\sqrt{3},\:x=-4\sqrt{3} are the roots.

Step-by-step explanation:

x=4\sqrt{3},\:x=-4\sqrt{3}

Considering the expression

x^2\:-\:48

Solving

x^2-48=0

x^2-48+48=0+48

x^2=48

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{48},\:x=-\sqrt{48}

Solving

x=\sqrt{48}

  = \sqrt{2^4\cdot \:3}

  \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

  = \sqrt{3}\sqrt{2^4}

  \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^m}=a^{\frac{m}{n}}

  \sqrt{2^4}=2^{\frac{4}{2}}=2^2

  =2^2\sqrt{3}

  =4\sqrt{3}

So,

x=4\sqrt{3}

Similarly,

x=-\sqrt{48}=-4\sqrt{3}

Therefore, x=4\sqrt{3},\:x=-4\sqrt{3} are the roots.

Keywords: roots, expression

Learn more about roots from brainly.com/question/3731376

#learnwithBrainly

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