Answer:
B'(3, 5)
Step-by-step explanation:
Rule for the translation of a point (x, y) by 'h' units left and 'k' units upwards,
(x, y) → (x - h, y + k)
If h = 4 and k = 3,
Following this rule coordinates of the image point of B will be,
B(7, 2) → B'(7 - 4, 2 + 3)
→ B'(3, 5)
Therefore, coordinates of the image point B' will be,
B'(3, 5)
Answer:
Step-by-step explanation:
The given trigonometric graph is symmetric about the y-axis.
This means it is a cosine function.
The basic is symmetric about the y-axis and has a y-intercept of 1.
Its range is
Since the given graph has y-intercept at -1 with the same range, it is the parent cosine function reflected in the x-axis.
Therefore its equation is
Answer:
A. y = (x -7)² +9
B. y = -(x +3)² -11
C. minimum, (7, 9)
D. maximum, (-3, -11)
Step-by-step explanation:
The general steps to rewriting the function in vertex form are ...
1. factor out the leading coefficient (if not 1) from the first two terms
2. add inside parentheses the square of half the x coefficient; subtract the same amount outside parentheses. The factor in front of the parentheses must be taken into account when adding the same amount outside.
3. rewrite the content of parentheses as a square, collect terms outside parentheses.
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A. y = x² -14x +58
y = (x² -14x) +58 . . . . . . . . . . step 1
y = (x² -14x +49) +58 -49 . . . step 2
y = (x -7)² +9 . . . . . . . . . . . . . step 3
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B. y = -x² -6x -20
y = -(x² +6x) -20
y = -(x² +6x +9) -20 -(-9)
y = -(x +3)² -11
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C. In vertex form, the function for vertical scale factor "a" and vertex (h, k) looks like ...
y = a(x -h)² +k
When a < 0, the vertex is a maximum (the graph opens downward); when a > 0, the vertex is a minimum (the graph opens upward).
The function of part A has a minimum at the vertex (7, 9). 9 is the minimum value.
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D. The function of part B has a maximum at the vertex (-3, -11). -11 is the maximum value.
