Answer: Surface area = 46 units². Step-by-step explanation: The formula for determining the total surface area of a rectangular prism is expressed
Answer with Step-by-step explanation:
We are given that if sum of several numbers is odd
We have to prove that at least one of the number is itself odd.
Suppose, we have three numbers
a=6 , b=7,d=8
Sum of numbers=6+7+8=21=Odd number
We know that sum of two odd numbers is always an even number.
Sum of an odd number and an even number is always an odd number.
If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.
Sum of even numbers is always an even number.
Hence, there are atleast one numebr is odd then the sum of several number is odd.
So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
A = 2.25 (3.14)
A = 7.065 square inches.
Next, we deduct the area of circle from area of square and the result would be 1.935 <span>in². So the answer for this would be option B.
Hope this answer helps.</span>
You just need to foil. 2x times 4x times 2x times 36 times 24 times 4x times 24times 36. then solve.
Answer:
Volume of cuboid = 300 in³
Surface area of cuboid = 280 in²
Step-by-step explanation:
Given:
Length = 10 in
Width = 5 in
Height = 6 in
Find:
Volume of cuboid
Surface area of cuboid
Computation:
Volume of cuboid = [L][B][H]
Volume of cuboid = [10][5][6]
Volume of cuboid = 300 in³
Surface area of cuboid = 2[lb][bh][hl]
Surface area of cuboid = 2[(10)(5) + (5)(6) + (6)(10)]
Surface area of cuboid = 2[50 + 30 + 60]
Surface area of cuboid = 2[140]
Surface area of cuboid = 280 in²
