Hello from MrBillDoesMath!
Answer:
x = -3, 4
Discussion:
The zeroes of f(x) are the x values where
2x + 6 = 0 => x = -3
and
x - 4 = 0 => x = 4
Thank you,
MrB
1) 1/2
2) 7/8
3) 4
4) 19/8 = 2 3/8
The answer to your question is -1 < y < 3
-
Answer:
27
Step-by-step explanation:
Let <em>g </em>be Gabrielle's age and <em>m </em>be Mikhail's age.
We can turn the statements the problem gives us into mathematical expressions to help us solve.
Gabrielle's age is two times Mikhail's age:
<em>g </em>= 2<em>m</em>
The sum of their ages is 81:
<em>g </em>+ <em>m </em>= 81
This gives us a system of equations that will allow us to solve for Gabrielle's age.
<em>g </em>+ <em>m </em>= 81
(2<em>m</em>)<em> </em>+ <em>m </em>= 81
3<em>m </em>= 81
<em>m</em> = 
<em>m </em>= 27
If we need to solve for Gabrielle's age, we can do the following.
<em>g </em>= 2<em>m</em>
2(27)<em> </em>= <em>g</em>
54 = <em>g</em>
g = 54
Mikhail's age is 27.
Gabrielle's age is 54.
Answer:
i can help with a littel bit of it
Step-by-step explanation:
1. answer
29±95‾‾‾√9
x
=
−
2
9
±
95
i
9
=−0.222222+1.08298
x
=
−
0.222222
+
1.08298
i
=−0.222222−1.08298
x
=
−
0.222222
−
1.08298
i
Find the Solution for:
92+4+11=0
9
x
2
+
4
x
+
11
=
0
using the Quadratic Formula where
a = 9, b = 4, and c = 11
=−±2−4‾‾‾‾‾‾‾‾√2
x
=
−
b
±
b
2
−
4
a
c
2
a
=−4±42−4(9)(11)‾‾‾‾‾‾‾‾‾‾‾‾√2(9)
x
=
−
4
±
4
2
−
4
(
9
)
(
11
)
2
(
9
)
=−4±16−396‾‾‾‾‾‾‾‾‾√18
x
=
−
4
±
16
−
396
18
=−4±−380‾‾‾‾‾√18
x
=
−
4
±
−
380
18
The discriminant 2−4<0
b
2
−
4
a
c
<
0
so, there are two complex roots.
Simplify the Radical:
=−4±295‾‾‾√18
x
=
−
4
±
2
95
i
18
=−418±295‾‾‾√18
x
=
−
4
18
±
2
95
i
18
Simplify fractions and/or signs:
=−29±95‾‾‾√9
x
=
−
2
9
±
95
i
9
which becomes
=−0.222222+1.08298
x
=
−
0.222222
+
1.08298
i
=−0.222222−1.08298
2. Answer:
=−38±895‾‾‾‾√40
x
=
−
3
8
±
895
i
40
=−0.375+0.747914
x
=
−
0.375
+
0.747914
i
=−0.375−0.747914
x
=
−
0.375
−
0.747914
i
3. Answer:
=0=−74
x
=
0
x
=
−
7
4
=0
x
=
0
=−1.75
Find the Solution for
82+14+0=0
8
x
2
+
14
x
+
0
=
0
using the Quadratic Formula where
a = 8, b = 14, and c = 0
=−±2−4‾‾‾‾‾‾‾‾√2
x
=
−
b
±
b
2
−
4
a
c
2
a
=−14±142−4(8)(0)‾‾‾‾‾‾‾‾‾‾‾‾√2(8)
x
=
−
14
±
14
2
−
4
(
8
)
(
0
)
2
(
8
)
=−14±196−0‾‾‾‾‾‾‾√16
x
=
−
14
±
196
−
0
16
=−14±196‾‾‾‾√16
x
=
−
14
±
196
16
The discriminant 2−4>0
b
2
−
4
a
c
>
0
so, there are two real roots.
Simplify the Radical:
=−14±1416
x
=
−
14
±
14
16
=016=−2816
x
=
0
16
x
=
−
28
16
=0=−74
x
=
0
x
=
−
7
4
which becomes
=0
x
=
0
=−1.75
i hope this helps
