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Aliun [14]
3 years ago
8

PLEASE HELP I WILL MARK BEAINLIST

Mathematics
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

Is it 1,512?

Step-by-step explanation:

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PLS EXPLAIN HOW THESE SEQUNCE IS FORMED<br><br>ALL ODD NUMBERS
scoundrel [369]

Answer:

7,21,27,81,87, 261, 267....

Step-by-step explanation:

All odd number series from the given figure is

7, 21, 27, 81 , 87....

We can write this series as

7, 7 x 3 , (7x3)+6, ((7x3)+6)x3, (((7x3)+6)x3)+6....

7, 21, 21+6 , 27 x 3, 81+6...

Now, the next term of the series will be

=((((7x3)+6)x3)+6) x 3

= 87 x 3

= 261

And another term of the series will be

= 261 +6

= 267

7,21,27,81,87, 261, 267....

8 0
3 years ago
Can someone help me? please
Black_prince [1.1K]

Answer:

I can but not willing right now so sorry

4 0
3 years ago
What is the estimate difference between 2.97 1 2/11​
zheka24 [161]

Answer:

2

Step-by-step explanation:

Estimate 1 2/11 to 1.

Estimate 2.97 to 3.

3 - 1 = 2

3 0
3 years ago
Please answer this in two minutes
spayn [35]

Answer:

I answered it

Step-by-step explanation:

I answered it

3 0
3 years ago
Read 2 more answers
Shown here are four frequency distributions. Each is incorrectly constructed. State the reason why.
Tanya [424]

Answer/Step-by-step explanation:

a. The the class width for the 1st, 2nd, 3rd, and 5th row equal 5 in the frequency distribution. Whereas, in the 4th row, the class width is 4 (49 - 45). This makes the construction incorrect.

b. Here, the upper limit of each consecutive class was used as the lower limit if the next class. For example, 9 is a member of the first class, which is the upper limit if the class in the first row, it ought not to be included as a member of the next class in the second row.

c. In the 3rd row, the lower limit of the class should be 133, NOT 138.

d. Different class width were used.

Row 1 class width = 13 - 9 = 4

Row 2 class width = 19 - 14 = 5

Row 3 class width = 25 - 20 = 5

Row 4 class width = 28 - 26 = 2

Row 5 class width = 32 - 29 = 3

8 0
3 years ago
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