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3 years ago

KEYNA EXCHANGES $150 FOR BRITISH POUNDS. SUPPOSE THE CONVERSION RATE IS = $1.60. HOW MANY POUNDS SHOULD SHE RECEIVE

Mathematics

1 answer:

nydimaria [60]3 years ago

3 0

I didn't quite understand the conversion rate but I believe the answer would be that Keyna will receive 93.75 pounds.

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Alfredo bought a fishing pole for 60% off it’s original price of $97. If the tax was 4% ( of the sale price), how much did Alfre

maxonik [38]

Answer:

40.4

Step-by-step explanation:

Well...you see, 60% of $97 is equal to 58.2. you can get this by multiplying 97 by 0.60.

so subtract 97 by 58.2 and you will get 38.8, now you will add the tax which is and extra add-on to the prices full value

and it's a 4% tax so you will add for percent to 38.8,

basically multiply 38.8 times 0.04 and you will get 1.6 which you will have to add the your amount to get 40.4.

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2 years ago

What is the denominator of 23/24

harina [27]

The denominator is 24 in the fraction

7 0

3 years ago

Read 2 more answers

What is 8blank7 hundred divided by 4 equal

Gnoma [55]

$\frac{870}{4} = \frac{435}{2} 
$

<span>(Decimal: 217.5)
</span>
For if its
$\frac{8700}{4}$

Then is $=2175$

~ Hope this helps

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2 years ago

PLEASE HELP ASAP! I don’t recall how to do this!

MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

$(1.05)^x=1.885$

In order to solve for x, we have to get it out from its position of an exponent. Do that by taking the natural log of both sides:

$ln(1.05)^x=ln(1.885)$

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

$x=\frac{ln(1.885)}{ln(1.05)}$

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

$ln(x*x^2)=5$

Simplifying gives you

$ln(x^3)=5$

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

$ln(x)=\frac{5}{3}$

Take the inverse ln by raising each side to e:

$e^{ln(x)}=e^{\frac{5}{3}}$

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

$\frac{1}{2}=e^{.1x}$

"Undo" that e by taking the ln of both sides:

$ln(.5)=ln(e^{.1x})$

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others. Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

$(2^2)^x-6(2)^x=-8$

Now we will bring over the -8 by adding:

$(2^2)^x-6(2)^x+8=0$

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution. Let's let $u=2^x$

When we do that, we can rewrite the polynomial as

$u^2-6u+8=0$

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor. Now we have to put it back in:

$2^x=4,2^x=2$

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

$2^2=2^x$

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

$2^x=2^1$

Now that the bases are the same, we can say that

x = 1

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2 years ago

1. 4x + 3(x-9) = 19

Dmitry_Shevchenko [17]

1) 4x + 3(x-9) = 19

or, 4x + 3x - 27 = 19

or, 7x = 19+27

or, 7x = 46

or, x = 46/7

◆ x = 6.57

2) 2(x-4) + 5x = 3

or, 2x - 8 + 5x = 3

or, 7x = 3+8

or, x = 11/7

◆ x = 1.57

3) 60 = 8y - 3(y-10)

or, 60 = 8y - 3y + 30

or, 60 - 30 = 5y

or, y = 30/5

◆ y = 6

4) 40 + 3c = 3 + 9(c-2)

or, 40 + 3c = 3 + 9c - 18

or, 40 + 3c = 9c - 15

or, 9c - 3c = 40 + 15

or, 6c = 55

◆ c = 9.166

I hope you understand..

Thank you...♥♥

5 0

1 year ago

Read 2 more answers