−1/3−(−5/6)=<br> PLS HELP

PLEASE HELP!!!! I DON'T KNOW THE ANSWERS!!

Alexus [3.1K]

the first one is a

the vertex is (5,-3)

5 0

3 years ago

Read 2 more answers

The following scatter plot represents the height of a basketball in seconds during a free throw shot.

zavuch27 [327]

The function is not treated as linear because whenever we throw the thing in the air it traces the path of the parabola which is quadratic. Then the quadratic equation is y = -1.25x² + 7.35x + 3.2.

<h3>What is a quadratic equation?</h3>

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

The following scatter plot represents the height of a basketball in seconds during a free throw shot.

(a) A student chose to model the data with the function, y = 0.9286x + 9.0571 . Then the function is not treated as linear because whenever we throw the thing in the air it traces the path of the parabola which is quadratic.

(b) Write a function

We know that the quadratic equation is given as ax² + bx + c = y

This will pass through the points (1, 9.3), (2, 12.9), and (3, 14). Then we have

$\rm a + b + c = 9.3 \ \ \ \ \ \ \ ...1\\\\4a + 2b + c = 12.9 \ \ \ ...2\\\\9a + 3b + c = 14 \ \ \ \ \ \ ...3$

On solving the equations 1, 2, and 3. Then we have

a = -1.25, b = 7.35, and c = 3.2

Then the quadratic equation will be

y = -1.25x² + 7.35x + 3.2

More about the quadratic equation link is given below.

brainly.com/question/2263981

#SPJ1

4 0

2 years ago

A $400 suit is marked down to $260. Find the percent of markdown.

notka56 [123]

The answer is B. -$140

4 0

3 years ago

Read 2 more answers

Vitamin D, whether ingested as a dietary supplement or produced naturally when sunlight falls on the skin, is essential for stro

tigry1 [53]

Answer:

a) The 98% confidence interval would be given (0.182;0.218).

b) We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

c) If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

d) Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

Step-by-step explanation:

Data given and notation

n=2700 represent the random sample taken

X represent the people in England who are deficient in Vitamin D

$\hat p=0.2$ estimated proportion of England people who are deficient in Vitamin D

$\alpha=0.02$ represent the significance level

Confidence =0.98 or 98%

z would represent the statistic (variable of interest)

p= population proportion of England people who are deficient in Vitamin D

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 98% confidence interval the value of $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.33$

And replacing into the confidence interval formula we got:

$0.20 - 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.182$

$0.20 + 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.218$

And the 98% confidence interval would be given (0.182;0.218).

Part b

We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

Part c

If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

Part d

Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

3 0

3 years ago

For each part of this problem, show all your work and write a probability statement.

AlladinOne [14]

Answer:

Follows are the answer to the given point.

Step-by-step explanation:

In point 1:

$\to P( \text{number of response}) = \frac{192}{338} \\$

$= \frac{96}{169}\\\\= 0.56$

In point 2:

$\to P| \text{(Zoloft and fill response)}| = \frac{27}{338}$

$= 0.079$

In point 3:

$\to P(\frac{\text{ full or partial}}{\text{St. John's Wort}}) = \frac{\frac{43}{338}}{\frac{113}{338}}$

$= \frac{43}{338} \times \frac{338} {113}\\\\= \frac{43}{113}\\\\= 0.38$

In point 4:

$\to P(\frac{\text{Placebo}}{\text{full or response}}) = P(\frac{(\text{Placebo} \cap \text{full or response})} {\text{p(full response)}})$

$= \frac{\frac{79}{338}}{ 1- \frac{91}{338}} \\\\ = \frac{\frac{79}{338}}{ \frac{338-91}{338}} \\\\ = \frac{\frac{79}{338}}{\frac{247}{338}} \\\\ = \frac{79}{338} \times \frac {338}{247} \\\\= \frac{79}{274} \\\\ = 0.28$

4 0

3 years ago

−1/3−(−5/6)= PLS HELP