Answer:
4
Step-by-step explanation:
Step 1: find (r- s) or r(x) - s(x)
r(x) - s(x) = 3x - 1 - (2x + 1)
r(x) - s(x) = 3x - 1 - 2x - 1 (distribute the -1 to 2x and 1)
r(x) - s(x) = x - 2 (combine like terms, 3x + (-2x) = x, -1 + (-1) = -2)
so r(x) - s(x) = x - 2, or (r - s)(x) = x - 2
Step 2: Plug in 6 to 'x' and find (r - s)(x)
(r - s)(6) = 6 - 2 = 4
Answer:
147 purple jelly beans
Step-by-step explanation:
15% of 980 is 147
Gravity always acts downward on every object on earth. Gravity multiplied by the object's mass produces a force called weight. Although the force of an object's weight acts downward on every particle of the object, it is usually considered to act as a single force through its balance point, or center of gravity.
Answer:
<em>Functions:</em>
3. The chart with arrows
4. The graph
<em>Not Functions:</em>
1. (1,1), (2,2), (3,3), (1,4)
2. (1,17), (0,16), (0,15), (-2,17)
Step-by-step explanation:
Functions do not have repeating domains (x-coordinates).
Hope it helps!
Answer:
y_c = 2 + 10*x
Step-by-step explanation:
Given:
y'' = 0
Find:
- The solution to ODE such that y(0) = 2, y'(0) = 10
Solution:
- Assuming a solution y = Ce^(mt)
So, y' = C*me^(mt)
y'' = C*m^2e^(mt)
- Back substitute into given ODE, we get:
y'' = C*m^2e^(mt) = 0
e^(mt) can not be equal to zero
- Hence, m^2 = 0
m = 0 , 0 - (repeated roots)
- The complimentary function for repeated roots is:
y_c = (C1 + C2*x)*e^(m*t)
y_c = C1 + C2*x
- Evaluate @ y(0) = 2
2 = C1 + C2*0
C1 = 2
-Evaluate @ y'(0) = 10
y'(t) = C2 = 10
Hence, y_c = 2 + 10*x
