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3 years ago

Uhh help?? I’m highly confused I just want answers

Mathematics

1 answer:

mihalych1998 [28]3 years ago

3 0

Answer:

1) x = 5√3, y = 5

2) x = 16, y = 8

3) x = 10, y = 5

4) m = 9√15/10, n = 9√5/10

5) x = 3√3/2, y = 3/2

6) x = 6√5, y = 3√5

7) x = 5, y = 5

8) x = 5√2, y = 5

9) a = 2, b = √2

10) m = 10√6/3, n = 5√6/3

Explanation:

For special right triangles, there is a certain side ratio that applies due to the angle measurements which are opposite of the corresponding angles.

For 30° - 60° - 90° triangles (Scalene Right), we can use x as a marker for the side opposite of 30°, the side opposite of the 60° angle will be x√3, and the side opposite of the 90° angle will be 2x.

For 45° - 45° - 90° triangles (Isosceles Right),

Both 45° angles can be thought of as x, and the 90° angle can be thought of as x√2.

This is all computed as a result of the trigonometric functions:

SOH CAH TOA.

This is a shortcut for these specific triangles.

If you do not have the side marked as x, just do the inverse operation to get it.

90° is always opposite of the hypotenuse (longest side of a triangle; looks like a slant)

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I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

Make a table for y=-x+4

GalinKa [24]

Answer:

X | Y

---------

0 | 4

2 | 2

4 | 0

6 | -2

10| -6

Step-by-step explanation:

hope it helps :D

3 0

3 years ago

Solve for x.

exis [7]

Answer:

11.2

Step-by-step explanation:

tan( <em>angle </em>) = <em>opposite / adjacent</em>

8 0

3 years ago

First to answer gets brainliest

skad [1K]

Answer:

Step-by-step explanation:

Because you can't do -x+1 so it would be (1,0) and then you have x^2 +3x-4 which is (-5,6)

6 0

3 years ago

GEOMETRY! PLEASE SHOW YOUR WORK. (updated picture)

Orlov [11]

Given:

The base of the given triangle has two part:

Left( left side of the hypotenuse) = 25

Right ( right side of the hypotenuse) = x

The altitude (h) = 60

To find the value of x.

Formula:

By Altitude rule we know that, the altitude of a triangle is mean proportional between the right and left part of the hypotenuse,

$\frac{left}{altitude} =\frac{altitude}{right}$

Now,

Putting,

left = 25, altitude = 60 and right = x we get,

$\frac{25}{60} =\frac{60}{x}$

or, $(25)(x )=(60)(60)$ [ by cross multiplication]

or, $x = \frac{3600}{25}$

or, $x = 144$

Hence,

The value of x is 144.

6 0

3 years ago

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