<h2>
Hello!</h2>
The answer is:
The x-coordinate of the solution to the system of equations is:
<h2>
Why?</h2>
We can solve the problem writing both equations as a system of equations.
So, we are given the equations:
Then, solving by reduction we have:
Multiplying the first equation by 2 in order to reduce the variable "x", we have:
Now, substituting "y" into the first equation, to isolate "x" we have:
Hence we have that the x-coordinate of the solution to the system of equations is
Have a nice day!
Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
where p is the number of positive outcomes (yes) and q is the number of negative outcomes (no).
= 0.0337 or 3.37%
answer is A.
Answer:
Well a linear equation is in a straight line. To show it was not linear on a coordinate grid the slope would not be a straight line
Step-by-step explanation:
Answer:
The answer would be C because b=+16 which means that it intercepts line y at 16, which is shown in the graph.
Step-by-step explanation:
