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Maurinko [17]
3 years ago
10

Captain Jessica has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless band of thiev

es. The Captain has probability 4/9 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 1/4 ​​.If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships?
Mathematics
1 answer:
erik [133]3 years ago
6 0

Answer: Probability that both the pirate and the Captain hit each other's ships is \frac{1}{9}

Step-by-step explanation:

since we have given that

Probability that the captain hits the pirate ship is given by

\frac{4}{9}

Probability that the pirate hits the Captains's ship is given by

\frac{1}{4}

So, we have to find the "Probability that both the pirate and the Captain hit each other's ship"  is given by

P(\text{Captain hits})\times P(\text{ Pirates hit})\\\\=\frac{4}{9}\times \frac{1}{4}\\\\=\frac{1}{9}

Hence, probability that both the pirate and the Captain hit each other's ships is \frac{1}{9}

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Answer:

12n^2-5n-2

The expression (3n-2)(4n+1) can be factored with the Distributive Property. It cannot be factored with a Least Common Multiple (LCM), for instance, because the terms within each set of parentheses are completely simplified.

Step-by-step explanation:

Part I

.1. (3n-2)(4n+1)\\2. F.O.I.L.: 12n^2+3n-8n-2\\3. Simplify: 12n^2-5n-2\\

Good luck to you!

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\large\underline{\underline{\red{\rm\blue{\longmapsto} Step-by-step\: Explanation:-}}}

Given to points to us are :-

  • ( 3 , -6 )
  • ( -1 , -8 )

( As these are plotted on graph with yellow dots .)

Now , we can use Distance Formula , which is :-

\boxed{\pink{\tt Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}}

Here ,

  • x1 = 3 .
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  • y2 = (-8).

<u>→ Substituting the respective values , </u>

⇒ Distance = √ [ { 3 - (-1)}² + { -6 -(-8)²} ] .

⇒ Distance = √ (3+1)² + (8-6)²

⇒ Distance = √ 4² + 2²

⇒ Distance = √ 16 + 4

⇒ Distance = √20 = √4 × √5

⇒ Distance = 4√5units .

<u>Hence the distance between two points is 4√5u.</u>

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Step-by-step explanation:

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