Question

Captain Jessica has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless band of thieves. The Captain has probability 4/9 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 1/4 ​​.If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships?

Answer 1

Answer: Probability that both the pirate and the Captain hit each other's ships is $\frac{1}{9}$

Step-by-step explanation:

since we have given that

Probability that the captain hits the pirate ship is given by

$\frac{4}{9}$

Probability that the pirate hits the Captains's ship is given by

$\frac{1}{4}$

So, we have to find the "Probability that both the pirate and the Captain hit each other's ship"  is given by

$P(\text{Captain hits})\times P(\text{ Pirates hit})\\\\=\frac{4}{9}\times \frac{1}{4}\\\\=\frac{1}{9}$

Hence, probability that both the pirate and the Captain hit each other's ships is $\frac{1}{9}$