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LUCKY_DIMON [66]
3 years ago
7

Look at my profile pic..... friend me!! 2+2=?

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0

2 + 2 = 22

its basic math, obviously *sashays*

iren2701 [21]3 years ago
5 0

Answer:

oh i know this one its 4 lm.ao

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Softa [21]

2b^3 -5 b^2 +b+2. R 9/ b-4

Use synthetic division

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2 years ago
(WILL MARK BRAINIEST PLEASE ASSIST) Define the inverse secant function by restricting the domain of the secant function to the i
Svetradugi [14.3K]

Answer:

  see the attachment

Step-by-step explanation:

The graph attached shows the secant function in red. The restriction to the interval [0, π/2] is highlighted by green dots, and the corresponding inverse function is shown by a green curve.

The restriction to the interval [π/2, π] is highlighted by purple dots, and the corresponding inverse function is shown in purple.

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3 years ago
The number part of a term is called?
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Answer: The number part of a term is called the coefficient.

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3 years ago
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Rework problem 15 in section 2 of Chapter 5 of your textbook about the growing suburb and the declining city using the following
bazaltina [42]

Answer:

16 years.

Step-by-step explanation:

Please consider the complete question.

Assume that the suburb has a population of 686,000 and is growing at a rate of 4000 per year. Assume that the city has a population of 942,000 and is declining at a rate of 12000 per year. In how many years will the populations of the suburb and the city be equal?

Let x represent number of years.  

Growth function would be G(x)=4000x+686,000 and decline function would be D(x)=942,000-12,000x.

To find the time when both populations will be equal, we will equate both functions as:

4000x+686,000=942,000-12,000x

4000x+12,000x+686,000=942,000

16,000x+686,000=942,000

16,000x=942,000-686,000

16,000x=256,000

\frac{16,000x}{16,000}=\frac{256,000}{16,000}

x=16

Therefore, in 16 years the populations of the suburb and the city will be equal.

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3 years ago
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C

Step-by-step explanation:

All others can be proved false.

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3 years ago
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