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2 years ago

What is the range of the function y=2sin x

Mathematics

2 answers:

statuscvo [17]2 years ago

7 0

take the absolute value of the coefficient (2)

then the lower bound is the negative of that (-2)

so the range is [-2,2]

Dmitrij [34]2 years ago

7 0

Answer:

Range: [-2, 2] {y | -2 ≤ y ≤ 2}

Step-by-step explanation:

The given function is y = 2sinx

We have to find the range of the given function.

Since at y-axis sine function has the variance between -1 to 1 so range of y = sinx is [-1, 1]

and if the amplitude of sine function is 2 then sine function will vary from -2 to 2 which implies that range of y = 2 sinx will be [-2, 2]

So range of y = 2sinx is [-2, 2]

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For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr

pshichka [43]

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables $X_i$ with the following distribution:

$X_i Bin (1,p) = Be(p)$ bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:

$Z = \sum_{i=1}^N X_i$

From the info given we know that $N \sim Bin (M,q)$

We need to proof that $Z \sim Bin (M, pq)$ by the definition of binomial random variable then we need to show that:

$E(Z) = Mpq$

$Var (Z) = Mpq(1-pq)$

The deduction is based on the definition of independent random variables, we can do this:

$E(Z) = E(N) E(X) = Mq (p)= Mpq$

And for the variance of Z we can do this:

$Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2$

$Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2$

And if we take common factor $Mpq$ we got:

$Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]$

And as we can see then we can conclude that $Z \sim Bin (M, pq)$

8 0

3 years ago

Anyone who answers correctly gets brainlist!

pochemuha

Answer:

Step-by-step explanation:

A is the procedure

5 0

2 years ago

3[5x - 4] - [-30 - 45x]

Nimfa-mama [501]

$3(5x - 4) - (-30-45x)$
$= 15x - 12 + 30 + 45x$ <- Distributive Property
$=60x + 18$ <- Combine Like Terms

If you're trying to solve for 0:

$0 = 60 x + 18$
$-18 = 60x$ <- Subtracted 18 from both sides
$x = \frac{-18}{60} = \frac{-9}{30}$ <- Divided both sides by 60 and then simplified.

$x = \frac{-9}{30}$ <- Fraction Form
$x = -0.3$ <- Decimal Form

Give Brainliest for simple answer plz :P

3 0

2 years ago

Read 2 more answers

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!

shepuryov [24]

Answer:

Step-by-step explanation:

5 0

2 years ago

What is the solution to this system of equations?<br>x-2y=15<br>2x + 4y=-18

jeyben [28]

Answer:

x = 3; y = -6

Step-by-step explanation:

x - 2y = 15

2x + 4y = -18

Multiply both sides of the first equation by 2. Write the second equation below it, and add the two equations.

2x - 4y = 30

(+) 2x + 4y = -18

---------------------------

4x = 12

4x/4 = 12/4

x = 3

Now we substitute 3 for x in the first equation and solve for y.

x - 2y = 15

3 - 2y = 15

-2y = 12

y = -6

Answer: x = 3; y = -6

4 0

3 years ago