Given: LMNB is a square, LM = 20cm, P∈ LM , K ∈ PN , PK = 1 5 PN, LP = 4 cm Find: Area of LPKB
1 answer:
Answer:
80 cm²
Step-by-step explanation:
Trapezoid LPKB has area ...
A = (1/2)(b1 +b2)h = (1/2)(4 +20)(20) = 240 . . . . cm²
Triangle BPN has area ...
A = (1/2)bh = (1/2)(20)(20) = 200 . . . . cm²
Triangle BKN has a height that is 4/5 the height of triangle BPN, so will have 4/5 the area:
ΔBKN = (4/5)(200 cm²) = 160 cm²
The area of quadrilateral LPKB is that of trapezoid LPNB less the area of triangle BKN, so is ...
240 cm² - 160 cm² = 80 cm²
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Answer:
The length of minor arc AB is π ft
Step-by-step explanation:
The formula of the length of an arc in a circle is L = × 2πr, where α is the central angle subtended by the arc, and r is the radius of the circle
∵ The radius of the circle is 4 ft
∴ r = 4
∵ ∠AOB is a central angle subtended by minor arc AB
∵ m∠AOB = 50°
∴ α = 50°
Substitute the values of r and α in the rule above
∵ L = × 2π(4)
∴ L = π
∴ The length of minor arc AB is π ft
Step-by-step explanation:
Answer is in the photo
Hope it helllps
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