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3 years ago

What value of x makes the equation square root of x-5=4 true?

Mathematics

2 answers:

AveGali [126]3 years ago

8 0

$x-5=4 \\ \\x=4+5\\ \\x=9$

nadya68 [22]3 years ago

6 0

X-5=4
x=9

Therefore it is 9

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Somebody help me out

Bumek [7]

The number that produces an irrational number when multiplied by 0.4 is 3π. The correct option is A. $3\pi$

To determine which number produces an irrational number when multiplied by 0.4

First and foremost, 0.4 is a rational number.

A rational number is a number that is of the form $\frac{p}{q}$ where p and q are integers and q is not equal to 0.

0.4 can be written as $\frac{4}{10}$ or $\frac{2}{5}$ , hence, it is a rational number.

Now,

Any irrational number when multiplied by a rational number other than zero will also be irrational.

Therefore, we are to determine which of the given options is an irrational number.

For option A. 3π

π is an irrational number, therefore 3π is also an irrational number

For option B. 0.444...

0.444... can be expressed as 4/9, therefore it is a rational number

For option C. $\sqrt{9}$

$\sqrt{9}$ = 3, which can be expressed as 3/1, therefore it is a rational number

For option D. $\frac{2}{7}$

$\frac{2}{7}$ is a rational number

The only irrational number among the given options is 3π

Hence, the number that produces an irrational number when multiplied by 0.4 is 3π. The correct option is A. $3\pi$

Learn more here: brainly.com/question/11763957

8 0

2 years ago

"Find the point at which the line touches the circle" I really need help no one helped last time...

Troyanec [42]

The solution for a system of equations will be when the graphs touch each other, or intersect, and that happens when both equations equate each other, so, let's do so,

$\bf \begin{cases}
\boxed{y}=3x+10\\
-------\\
x^2+y^2=10\\
y^2=10-x^2\\
y=\sqrt{10-x^2}
\end{cases}\qquad \qquad \boxed{3x+10}=\sqrt{10-x^2}
\\\\\\
\textit{now we square both sides}\qquad (3x+10)^2=(\sqrt{10-x^2})^2
\\\\\\
(3x+10)^2=10-x^2\implies 9x^2+60x+100=10-x^2
\\\\\\
10x^2+60x-90=0\implies x^2+6x-9=0\implies (x+3)(x+3)=0
\\\\\\
x=
\begin{cases}
-3\\
-3
\end{cases}\qquad thus\qquad \boxed{x=-3}$

$\bf -------------------------------\\\\
\textit{now, when x = -3, what is \underline{y}?}\qquad y=3x+10\implies y=3(-3)+10
\\\\\\
y=-9+10\implies \boxed{y=1}\qquad \qquad therefore\qquad (\stackrel{x}{-3}~,~\stackrel{y}{1})$

6 0

3 years ago

describe and correct the error a student made finding the intercepts of the graph of the line 4x-6y=12

Kazeer [188]

Answer:

sorry????

Step-by-step explanation:

mmmmmmmmm?????

8 0

3 years ago

Find the area of a rectangle with a base of 5 feet and a height of 9 1/2 feet

gayaneshka [121]

The area of the rectangle is 47 1/2

7 0

3 years ago

TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streamin

choli [55]

Answer:

a) The 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

b) $n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51$

And rounded up we have that n=1831

Step-by-step explanation:

Data given and notation

n=2341 represent the random sample taken

X represent the people that they have watched digitally streamed TV programming on some type of device

$\hat p=0.55$ estimated proportion of people that they have watched digitally streamed TV programming on some type of device

$\alpha=0.01$ represent the significance level

Confidence =0.99 or 99%

z would represent the statistic for the confidence interval

p= population proportion of people that they have watched digitally streamed TV programming on some type of device

The population proportion present the following distribution:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}}$

Part a) Confidence interval

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.