For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
Answer:
Step-by-step explanation:
The absolute difference is 77-(-8)=85. The only option that is equivalent is
|-8|+77
Answer:
22.7%
Step-by-step explanation:
$230+($45x$0.42=248.90
That is the equation to solve it.
Answer:
No
Step-by-step explanation:
Assuming that you put the wrong sign for the second equation if you plug (2,7) into the two equations it only works for one equation.
