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nekit [7.7K]
3 years ago
9

Jjkvghcgvjvgkjvgjvgkh

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0

Answer:

sadfghjklyujthgnvb

Step-by-step explanation:

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Given: F(x) = x + 2 and G(x) = 3x + 5<br><br> (F*G) (x) =
vovangra [49]

Answer:

\boxed{(f \times g)(x) = 3 {x}^{2}  + 11x + 10}

Given:

f(x) =  x + 2 \\  \\ g(x) =  3x + 5

To Find:

(f \times g)(x) = f(x) \times g(x)

Step-by-step explanation:

=  > f(x) \times g(x) = (x + 2)( 3x + 5) \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   =x( 3x + 5) + 2(3x + 5)  \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   =3 {x}^{2}  + 5x + 6x + 10\\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   =3 {x}^{2}  + 11x + 10

5 0
3 years ago
Read 2 more answers
If -<br> 3- 12, what is the value of x?<br> 4<br> 00<br> O 18<br> 0 24
malfutka [58]

Answer:

8

Step-by-step explanation:

\frac{2}{3} = \frac{x}{12}

We make the denominator the same by multiplying \frac{2}{3} by 4.

\frac{8}{12} = \frac{x}{12}

Thus, x = 8.

6 0
2 years ago
PLEASE HELP!
Ierofanga [76]

Answer:

even number can be divided by two without areminder

3 0
3 years ago
Solve for x <br>−30=5(x−9)<br>x=​
babymother [125]

Answer:

Hi! The correct answer is x=3!

Step-by-step explanation:

<u><em>~Isolate the variable by dividing each side by factors that don't contain the variable~</em></u>

8 0
3 years ago
Read 2 more answers
The common difference ,d in an arithmetic sequence whose fourth term is 16 and whose seventh therm is 31
Natali [406]

Answer: d=5

Step-by-step explanation:

Arithmetic progression

An=a1+d(n-1)

An= nth term

A1= first term

D= common difference

N= nth position

We are given the 4th and 7th terms

For 4th term,n=4

A4=a1+d(4-1)

A4= 16

16= a1+d(4-1)

16= a1+3d........equation 1

For the 7th term,n=7

A7=a1+d(7-1)

A7= 31

31=a1+6d......equation 2

Bring them together

16=a1+3d

31=a1+6d

Subtract equation 1 from 2

So we have

15=3d

D=15/3

D=5

Therefore, the common difference is 5

3 0
3 years ago
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