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3 years ago

Irrotionalnumber I need a example

1 answer:

6 0

Irrational numbers are numbers that can not be written as a simple fraction. An example of one would be $\pi$ . Pi is about 3.14, but it goes on forever. You can not write pi as a simple fraction.

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Solve using any method. All work must be shown and handwritten.

Rashid [163]

Answer:

$x = - 3$

$y = 1$

Step-by-step explanation:

Write the system

$3x - y = - 10$

$x + y = - 2$

Solve by Elimination.

multiply the second equation by -3.

$3x - y = - 10$

$-3x - 3y = 6$

Add the Equations.

$- 4y = - 4$

$y = 1$

Plug this back in one of the equations.

$x + 1 = - 2$

$x = - 3$

8 0

3 years ago

Read 2 more answers

Quadrilateral ABCD?<br>

Mashutka [201]

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = $\sqrt{(7 - 2)^{2} + (4 - 4)^{2} }$

⇒ AD = $\sqrt{5^{2} }$

⇒ AD = 5

DC = $\sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }$

⇒ DC = $\sqrt{5^{2} }$

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = $\sqrt{(-2 - 2)^{2} + (-5 - 4)^{2} }$

⇒ AB = $\sqrt{(-4)^{2} + (-9)^{2} }$

⇒ AB = $\sqrt{16 + 81}$

⇒ AB = $\sqrt{97}$

BC = $\sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2} }$

⇒ BC = $\sqrt{9^{2} + 4^{2} }$

⇒ BC = $\sqrt{81 + 16}$

⇒ BC = $\sqrt{97}$

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

For more questions on quadrilateral, visit:

brainly.com/question/23935806

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6 0

1 year ago

Is 4x + the square root of y = 12 a linear function

ivolga24 [154]

I wouldn't say so, as if you rearrange that equation you get sqr root y = 12 - 4x. Then you square everything to get the value of y so you would end up with 144 - 16x^2.
Therefore, the x value has a power, so it would be a curved line

3 0

3 years ago

If two lines are perpendicular, which statement must be true?

Kryger [21]

Answer:

Their slopes are opposites

8 0

2 years ago

What is the equation in point-slope form of the line that passes through the points (7, 5)(7, 5) and (−4, −1)(−4, −1) ? y+4=116(

Alex Ar [27]

(7,5)(-4,-1)
slope = (-1-5) / (-4-7) = -6/-11 = 6/11

y - y1 = m(x - x1)
slope(m) = 6/11
(-4,-1)...x1 = -4 and y1 = -1
now we sub...pay close attention to ur signs
y - (-1) = 6/11(x - (-4) ...not done yet...
y + 1 = 6/11(x + 4) <===

6 0

3 years ago

Read 2 more answers

Irrotionalnumber I need a example​

Irrotionalnumber I need a example