Answer:
no
Step-by-step explanation:
The given lengths do not satisfy the Pythagorean theorem:
34² ≠ 33² +16²
1156 ≠ 1089 +256
The given sides do not form a right triangle.
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<em>Alternate solution</em>
You can also compute 34² -33² = (34+33)(34-33) = 67·1 = 67 ≠ 16².
Even simpler, a Pythagorean triple will never have zero or two even numbers. The numbers (16, 33, 34) cannot be a Pythagorean triple.
Answer:
![f(x) =\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
Hello!
Considering the parent function, as the most simple function that preserves the definition. Let's take the function given:
![g(x) = \sqrt[3]{x-5}+7](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx-5%7D%2B7)
To have the the parent function, we must find the parent one, let's call it by f(x).
![f(x) =\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%5Csqrt%5B3%5D%7Bx%7D)
This function satisfies the Domain of the given one, because the Domain is still
and the range as well.
Check below a graphical approach of those. The upper one is g(x) and the lower f(x), its parent one.
3 - 4z - 4 = 3z - 2 - z
-4z - 1 = 2z - 2
2z + 4z = -1 + 2
6z = 1
z = 1/6
Hope this helps!
So our ratio is 2:3, therefore we are looking for a multiple of 2 and a multiple of 3 that are proportional to this ratio. We can start by multiplying the ratio by 2, which gets us 4:6, which, since 4+6 is ten, is not a correct answer. If you continue the pattern of multiplying the ration with different numbers, you would eventually discover that, if you multiply the ratio by 5, you get 10:15. Since 10+15 is equal to 25, we know that this is the correct answer
Your model would equal 50,(20+20)=40 +(5+5)=10 .....40+10=50