Answer:
{x = 2 , y = -2
Step-by-step explanation:
Solve the following system:
{y = 4 - 3 x | (equation 1)
{y = x/2 - 3 | (equation 2)
Express the system in standard form:
{3 x + y = 4 | (equation 1)
{-x/2 + y = -3 | (equation 2)
Add 1/6 × (equation 1) to equation 2:
{3 x + y = 4 | (equation 1)
{0 x+(7 y)/6 = (-7)/3 | (equation 2)
Multiply equation 2 by 6/7:
{3 x + y = 4 | (equation 1)
{0 x+y = -2 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 6 | (equation 1)
{0 x+y = -2 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 2 | (equation 1)
{0 x+y = -2 | (equation 2)
Collect results:
Answer: {x = 2 , y = -2
2*13= 26
2*16= 32
the answer is 2
Answer:
The roots of the equation 2m²+3=m are non-real roots.
Step-by-step explanation:
Given equation:
2m²+3=m
2m²-m+3=0
Here, from the equation we can obtain the following values:
a = 2, b = -1, c = 3
Discriminant of an equation is given as:
D = b²-4ac
= (-1)²-4(2)(3)
= 1 - 21
= -20
Discriminant can tell what kinds of roots the equation have.
In our case, the discriminant is less than 0.
When D < 0, the roots of the equation are complex conjugates.(non-real)
