A linear approximation to the error in volume can be written as
... ∆V = (∂V/∂d)·∆d + (∂V/∂h)·∆h
For V=(π/4)·d²·h, this is
... ∆V = 2·(π/4)·d·h·∆d + (π/4)·d²·∆h
Using ∆d = 0.05d and ∆h = 0.05h, this becomes
... ∆V = (π/4)·d²·h·(2·0.05 + 0.05) = 0.15·V
The nominal volume is
... V = (π/4)·d²·h = (π/4)·(2.2 m)²·(6.8 m) = 25.849 m³
Then the maximum error in volume is
... 0.15V = 0.15·25.849 m³ ≈ 3.877 m³
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Essentially, the error percentage is multiplied by the exponent of the associated variable. Then these products are added to get the maximum error percentage.
Answer:
2
Step-by-step explanation:
It has the greatest value denomination in the number. We know that because it is the number followed by other numbers.
Best of luck
4x + 8.....the factor is 4
4(x + 2)
Because it is closer to 0 and -1
Answer:
64ft
Step-by-step explanation:
d = distance from the Earth/ft
t = time falling/s
d ∝ t²
d = kt²
<u>d = 16 and t = 4:</u>
16 = k(4)²
16 = 16k
k = ¹⁶/₁₆
k = 1
d = t²
<u>t = 8:</u>
d = (8)²
d = 64
