we are given

For finding asymptote , we can find limit


now, we can solve it


so, horizontal asymptote is
.............Answer
Answer:
Here we have the function:
y = f(x) = 3^x
Using the values:
x and (x + 1)
We need to find that the y-value increases by a factor of 3.
So we need to prove that:
f(x + 1) = 3*f(x).
Or we can see the quotient:
f(x + 1)/f(x) = 3
Here we can find the values:
f(x + 1) = y = 3^(x + 1)
f(x) = y' = 3^x
If we take the quotient, we get:

Here we can use the properties:


Using these in the quotient equation we get:

Then:


So we found that the y-value increases by a factor of 3 between any two points x₂ and x₁ such that: x₂ - x₁ = 1.
Can you put the question in English?
7,485 just do long division
Answer:
Rational form:
399/100 = 3 + 99/100
Continued fraction:
[3; 1, 99]
Possible closed forms:
399/100 = 3.99
log(54)≈3.988984
8/(3 π) + π≈3.9904190
1/2 (e! + 1 + e)≈3.989551
-(sqrt(3) - 3) π≈3.983379
(14 π)/11≈3.9983906
25/(2 π)≈3.978873
(81 π)/64≈3.976078
(2 e^2)/(1 + e)≈3.974446
(π π! + 2 + π + π^2)/(3 π)≈3.988765
2 π - log(4) - 3 log(π) + 2 tan^(-1)(π)≈3.987955
2 - 1/(3 π) + (2 π)/3≈3.988291
Step-by-step explanation: