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Leni [432]
2 years ago
12

If xy = 144, x + y = 30, and x > y, what is the value of x – y ?

Mathematics
1 answer:
Ad libitum [116K]2 years ago
8 0

Answer:

The value of x-y is 18

Step-by-step explanation:

From the question, we can deduced the following ;

xy = 144....eqn(1)

x+y=30.......eqn(2)

For eqn(2), we subtract y from both sides to make x the subject.

\implies x  +  y - y= 30 - y

\implies x= 30 - y

Putting that x=30-y into eqn(1) we obtain;

y(30 - y)=144

\implies  30y - {y}^{2} =144

\implies  0= {y}^{2} - 30 + 144

\implies  0= {y}^{2} - 24y - 6y+ 144

\implies  0=y(y- 24)- 6(y - 24)

\implies  0=(y- 6)(y - 24)

This implies that

y-6=0 or y-24=0

Hence, y=6 or y=24.

Therefore, when x=6 then y=24 and when x=24, then y=6 all satisfy the given equations.

But from the question, x>y.

This implies that,x=24 and y= 6

Thus, the value of x-y=24-6=18

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<h2>Answer:</h2>

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<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors R_1 and R_2 connected together in parallel, the total resistance R_T is given by;

\frac{1}{R_T} = \frac{1}{R_1}  + \frac{1}{R_2}              ---------(i)

<em>Make </em>R_2<em> subject of the formula;</em>

=> \frac{1}{R_2} = \frac{1}{R_T}  - \frac{1}{R_1}  

=> \frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}

=>   {R_2} = \frac{R_TR_1}{R_1 - R_T}       ---------------(ii)

From the question,

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Substitute these values into equation (ii) as follows;

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