Answer:
Every 10 seconds
Step-by-step explanation:
The bob crosses its midline whenever cos(2π(t-2)/20)=0.
Since cosθ=0 when θ=±π/2 + 2πn, we can find then the bob crosses its midline by solving:
2π(t-2)/20 = ±π/2 + 2πn
t-2 = ±5+20n
The solutions are when t = -3, 7, 17, 27, 37, ...
Therefore, the bob passes its midline every 10 seconds.
<u>Given</u><u>:</u>
- Base,b= 16 mm
- Perimeter, P =50mm
<u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u>
the area of a rectangle?
<u>Formula</u><u> </u><u>used:</u>
- Perimeter of rectangle = 2(l+b)
- Area of rectangle = length × breadth
<u>Solution</u><u>:</u>
Perimeter of rectangle = 2(l+b)
50 = 2l+2×16
50=2l+32
2l=50-32
2l=18
l=9
Now,
Area of rectangle = length × breadth
= 9 × 16
= 144 mm²
Answer:
E = \frac{25M}{L}
Step-by-step explanation:
To solve this, we can multiple each side by E and then divide each side by L:
Answer:
no solutions
Step-by-step explanation:
Subtract the two equations
3x+y=18
-(3x+y=16)
--------------------
0 + 0 = -2
0 does not equal negative 2
This is never true so there are no solutions
