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2 years ago

I need help with this please

Mathematics

1 answer:

jeka942 years ago

7 0

well, like this the ratio is 300:250. We will now simplify these numbers.

30:25 (divide by ten)

6:5(Divide by five)

Your final ratio is 6:5

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Evaluate 3n - 4 for n = -2

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Okay so 3n- 4 =?
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Then we simplify,
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Lastly the answer,
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3 years ago

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2 years ago

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In a lab, a substance was cooked by 42 C over a period of 7 hours at a constant rate. What was the change in temperature each ho

Mekhanik [1.2K]

Given that we have the change in temperature over 7 hours and we are looking for the change over 1 hour, we can divide the total change in temperature by 7. Thus, the change in temperature would be $\frac{42}{7} C^{\circ}$ .

Additionally, this can be solved by equations:

$\dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = \dfrac{x \,\textrm{C}^{\circ}}{1 \,\textrm{hour}}$

$1 \,\textrm{hour} \cdot \dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = x \,\textrm{C}^{\circ}$

$\dfrac{42}{7} \,\textrm{C}^{\circ} = x \,\textrm{C}^{\circ}$

$\dfrac{42}{7} = x$

By using two different methods, we can determine that the change each hour was equal to 42/7 C° per hour.

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3 years ago

Factorise x2 - 5x + 10

tatiyna

This equation does not factor...

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3 years ago

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