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3 years ago

Lola's Car's Gas Tank is 7/8 Full Would She Have More If She Had 4/5 Of a Tank. Why?

1 answer:

6 0

No she would not have a fuller tank if she had 4/5 of one instead of 7/8.
In this situation you need to convert the fractions so that they have common denominators.
In order to achieve this I multiplied both the numerator and the denominator of 7/8 by 5.
I also multiplied both the numerator and denominator of 4/5 by 8.
7/8*5=35/40.
4/5*8=32/40.
Now you can easily tell that 7/8 is larger than 4/5.

Hope this helps! (:

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1. Maximum is cleaning shrimp. He cleans 4 shrimp every minute. Use time in minutes as the independent quantity and the number o

shusha [124]

Answer:

Step-by-step explanation:

Relationship Equation between time and shrimps cleaned : S = 4T; Relationship is inversely proportional; Unit rate of change = 4

Given : 4 Shrimps cleaned every minute.

So, Shrimps cleaned 'S' = 4 times minutes taken 'T' ; S = 4T

The relationship between variables is proportional, as the dependent variable (shrimps) is constant multiples times the independent variable (time), & their ratio remains constant.

It is directly proportional, as both variables (shrimps & time) move in same direction. One variable increase or decrease, other variable same respectively.

Graph in this case is upward sloping curve from origin, because of direct proportional relationship respectively.

Unit rate of change denotes constant magnitude of change in a variable with other variable. It is 4 in this case, as time increases the shrimps.

6 0

2 years ago

Jun used 56 cm of ribbon to go around the edge of a rectangular lid. The lid was 13 cm long. What is the width of the lid?

maksim [4K]

Answer:

The width of the rectangular lid is 15 cm.

Step-by-step explanation:1. Let's review the information given to us to answer the question correctly:

Length of the ribbon used by Jun = 56 cmLength of the rectangular lid = 13 cm

2. What is the width of the lid? The ribbon used by Jun is equivalent to the perimeter of the rectangular lid, therefore:Perimeter = 2 * Length + 2 * WidthReplacing with the values we have:56 = 2 * 13 + 2 * Width56 = 26 + 2Width2Width = 56 - 262Width = 30Width = 30/2Width = 15

5 0

2 years ago

Read 2 more answers

Suppose the number of children in a household has a binomial distribution with parameters n=12n=12 and p=50p=50%. Find the proba

nadya68 [22]

Answer:

a) 20.95% probability of a household having 2 or 5 children.

b) 7.29% probability of a household having 3 or fewer children.

c) 19.37% probability of a household having 8 or more children.

d) 19.37% probability of a household having fewer than 5 children.

e) 92.71% probability of a household having more than 3 children.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

$n = 12, p = 0.5$

(a) 2 or 5 children

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934$

$p = P(X = 2) + P(X = 5) = 0.0161 + 0.1934 = 0.2095$

20.95% probability of a household having 2 or 5 children.

(b) 3 or fewer children

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002$

$P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0002 + 0.0029 + 0.0161 + 0.0537 = 0.0729$

7.29% probability of a household having 3 or fewer children.

(c) 8 or more children

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.1208$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.0537$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.0161$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.0029$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.0002$

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.1208 + 0.0537 + 0.0161 + 0.0029 + 0.0002 = 0.1937$

19.37% probability of a household having 8 or more children.

(d) fewer than 5 children

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002$

$P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208$

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 = 0.1937$

19.37% probability of a household having fewer than 5 children.

(e) more than 3 children

Either a household has 3 or fewer children, or it has more than 3. The sum of these probabilities is 100%.

From b)

7.29% probability of a household having 3 or fewer children.

p + 7.29 = 100

p = 92.71

92.71% probability of a household having more than 3 children.

5 0

3 years ago

Kristi invests $3,000 at a 7.25% annual simple interest rate, and her sister Kari invests $3,200 at a 6.25% annual simple intere

True [87]

Answer:

Kristi

Step-by-step explanation:

The formula for Simple Interest =

Principal × Rate × Time

For Kristi

Kristi invests $3,000 at a 7.25% annual simple interest rate,

Principal = $3000

Rate = 7.25% = 0.0725

Time = 1

Simple interest = $3000 × 0.0725 × 1

= $217.5

For Kari

Her sister Kari invests $3,200 at a 6.25% annual simple interest rate.

Principal = $3200

Rate = 6.25% = 0.0625

Time = 1

Simple interest = $3200 × 0.0625 × 1

= $200

From the above calculation, we can see that: Kristi will earn the greater amount of interest after one year

3 0

3 years ago

A wave with a frequency of 60 hertz would generate 60 wave crests every

V125BC [204]

Answer is every second

5 0

3 years ago