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4 years ago

Lola's Car's Gas Tank is 7/8 Full Would She Have More If She Had 4/5 Of a Tank. Why?

1 answer:

6 0

No she would not have a fuller tank if she had 4/5 of one instead of 7/8.
In this situation you need to convert the fractions so that they have common denominators.
In order to achieve this I multiplied both the numerator and the denominator of 7/8 by 5.
I also multiplied both the numerator and denominator of 4/5 by 8.
7/8*5=35/40.
4/5*8=32/40.
Now you can easily tell that 7/8 is larger than 4/5.

Hope this helps! (:

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gayaneshka [121]

Answer:

y=(x-4)²

Step-by-step explanation:

(a-b)²=a²-2ab+b²

(x-4)²=x²-2×x×4+4²

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3 years ago

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How to isolate scalars from a matrix

I am Lyosha [343]

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3 years ago

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goblinko [34]

Answer:

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Step-by-step explanation:

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3 years ago

Beth said the distance to school is 2.8 km. The actual distance is 3.5 km. What is the percent error

Rom4ik [11]

Answer:

20%

Step-by-step explanation: The percent of error formula is |(theoretical value-actual value)/actual value|=percent of error. Substitute the values in. |(2.8-3.5)/3.5|=|(-0.7)/3.5|=0.2. The percent equal to 0.2 is 20%.

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3 years ago

Please Help! will give brainlest!

zzz [600]

Answer:

$\theta = \frac{\pi}{3} , \pi, \frac{5\pi}{ 3}$

Step-by-step explanation:

we want to solve the following trigonometric equation:

$\displaystyle - 2 { \sin}^{2} (\theta )+ \cos( \theta) + 1 = 0, \: \theta \in [0,2\pi)$

The first step of solving trigonometric equation is to rewrite the equation in terms of one trigonometric function . With Pythagorean theorem, we know that sin²x=1-cos²x . It will be helpful to rewrite the equation in terms of one trig functions. Therefore, substitute 1-cos² $\theta$ in the place of sin² $\theta$ :

$\displaystyle - 2 (1 - \cos ^{2} ) + \cos( \theta) + 1 = 0, \: \theta \in [0,2\pi)$

simplify:

$\displaystyle\implies - 2 (1 - \cos ^{2} (\theta) + \cos( \theta) + 1 = 0, \: \theta \in [0,2\pi)\\\implies- 2 + \cos ^{2} (\theta)+ \cos( \theta) + 1 = 0, \: \theta \in [0,2\pi)\\\implies\cos ^{2} (\theta)+ \cos( \theta) -1 = 0$

Consider cos² $\theta\implies$ x. Thus,

$2 {x}^{2} + x - 1 = 0$

solving the quadratic equation yields:

${x}^{} = \frac{1}{2} \\ x = - 1$

back-substitute:

$\begin{cases} \cos( \theta) = \dfrac{1}{2} \\ \cos( \theta) = - 1 \end{cases} \theta \in[0,2\pi)$

take inverse trig in both sides

$\implies \begin{cases} \theta = \dfrac{\pi}{3} + 2n\pi\\\theta= \frac{5\pi}{3} + 2n\pi \\ \theta = \pi + 2n\pi\end{cases} \theta \in[0,2\pi) \\\\\implies\theta= \frac{\pi}{3}+\dfrac{2n\pi}{3},\theta\in [0,2\pi)\\\text{when n=0}\\ \implies \theta = \frac{\pi}{3} \\ \text{when n=1}\\ \theta= \pi\\ \text{when n=2}\\\theta=\frac{5\pi}{ 3}$

In conclusion,

$\displaystyle\theta = \frac{\pi}{3} , \pi, \frac{5\pi}{ 3}$

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2 years ago