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2 years ago

85.

Mathematics

1 answer:

Zanzabum2 years ago

4 0

Answer:

A. you need 2 1/2 ounces

B. you need 73,9 milliliters

Step-by-step explanation:

We have the ratio 1/2 ounces per gallon

And the mop bucket holds 5 gallons

Then we need to multiply 1/2*5

we got 2 1/2 ounces of desifectant per 5 gallons

1 ounces equal 29,57 milliliters

if we have 2 1/2 ounces then we multiply 2,5 *29,57

the answer is 73,9 milliliters

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lyudmila [28]

Answer:

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2 years ago

Is D the right answer please help!

Leto [7]

The correct answer is C.
-5 is not greater than -3. Negatives are tricky; remember that the closer a negative is to zero, the greater that quantity actually is.

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2 years ago

The perimeter of a rectangle is 24 cm. find the lengths of the sides of the rectangle giving the maximum area. enter the answers

Simora [160]

24=2*12
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2 years ago

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Lady_Fox [76]

Answer:

AC is 6.5 cm

Step-by-step explanation:

From trigonometric ratios:

$\sin( \theta) = \frac{opposite}{hypotenuse} \\$

opposite » 3 cm

hypotenuse » AC

angle » 28°

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3 0

2 years ago

Read 2 more answers

A hiker is hiking in a valley. The height of the valley is h(x,y)=4x2+y2 where x and y are the east-west and north-south distanc

Ainat [17]

Answer:

A. $\frac{\partial{h}}{\partial{t}}=0$

Step-by-step explanation:

A. The problems asked for 2 ways to solve it, expanding the equation with the substitution x(t)=2 cos(t) and y(t)=4 sin(t) to differentiate it . The other way is by chain rule.

Expanding and differentiating:

We start by substituting x(t)=2 cos(t) and y(t)=4 sin(t) in h(x,y)=4x2+y2:

$h(x,y)=4x^{2}+y^{2}= 4(2cos(t))^{2}+(4sin(t))^{2}\\h(x,y)=4(4cos^{2}(t))+(16sen^{2}(t))\\h(x,y)=16cos^{2}(t)+16sen^{2}(t)=16(sen^{2}(t)+cos^{2}(t))\\h(x,y)=16$

So, in the path that the hiker chose:

$\frac{\partial{h}}{\partial{t}}=0$

Chain rule:

We start differentiating h(x,y) using chain rule as follows:

$\frac{\partial{h}}{\partial{t}}= \frac{\partial{h}}{\partial{x}}\frac{\partial{x}}{\partial{t}}+\frac{\partial{h}}{\partial{y}}\frac{\partial{y}}{\partial{t}}$

Now, it´s easy to find all these derivatives:

$\frac{\partial{h}}{\partial{x}}=8x\\\frac{\partial{x}}{\partial{t}}=-2sin(t)\\\frac{\partial{h}}{\partial{y}}=2y\\\frac{\partial{y}}{\partial{t}}=4cos(t)$

Now we replace them in the chain rule, with the replacement x=2cos(t) and y=4sin(t) in the x,y that are left and we operate everything:

$\frac{\partial{h}}{\partial{t}}= 8x(-2sin(t))+2y(4cos(t)$

$\frac{\partial{h}}{\partial{t}}= 8(2cos(t))(-2sin(t))+2(4sin(t))(4cos(t)$

$\frac{\partial{h}}{\partial{t}}= -32cos(t)sin(t)+32sin(t)cos(t)$

$\frac{\partial{h}}{\partial{t}}= 0$

This will be our answer

6 0

2 years ago