Important: Please use " ^ " to indicate exponentiation:
<span>"f(x) =x^2 to the number of x-intercepts in the graph of g(x) = x^2 +2."
Notes: the graph of f(x) = x^2 is a vertical parabola that opens up. It has its vertex at (0,0). This is the only point at which f(x)=x^2 has a horiz. intercept.
g(x) = x^2 + 2 has a graph that looks the same as that of f(x) = x^2, EXCEPT that the whole graph is moved 2 units UP. This new graph never touches or intersects the x-axis. Therefore, g(x) has NO horiz. intercepts (no x-int.).
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Hello :
x²- 6x + 8 = x² - 2(3)(x) +8
= (x² -2(3)(x) +9) - 9 + 8
= ( x - 3 )² - 1²
= (x - 3 + 1 ) (x - 3 - 1 )
x²- 6x + 8 = (x - 2 ) ( x - 4 )
x - ∞ 2 4 + ∞
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x - 2 -------- 0 +++++ +++++++
x - 4 --------- -------- 0 +++++
(x - 2 ) ( x - 4 ) +++ 0 ------ 0 ++++++
x2 − 6x + 8 > 0 the solution in : ]-∞:2[ U ]4;+∞[
Given that variance of a data set is:
Variance=σ²
the standard deviation is the square root of the variance:
thus
standard deviation= √(variance)
variance,σ²=104.04
thus
std deviation=√σ²=√104.04
thus
σ=10.2
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