3 years ago

A building contractor examined 6 floor joists in a home and found that they had the following widths:

Mathematics

1 answer:

miss Akunina [59]3 years ago

8 0

Answer:

Step-by-step explanation:8 inches

89 is the answe 89

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The graph of a linear relationship is shown below. Does this graph show a proportional relationship?

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Write a rule that represents the function. <br> (1,1/2),(2,1/4),(3.1/8),(4,1/16),(5,1/32)

ratelena [41]

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

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3 years ago