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Black_prince [1.1K]
4 years ago
5

Use the distributive property to simplify the following expression 4x(2x-6)

Mathematics
1 answer:
Drupady [299]4 years ago
3 0
4x (2x - 6)

8x - 24x 

= -16x

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2,000 + 0.03x

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3 years ago
Can someone give a correct answer to this? idk what im doing! thanks :)
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 The regular rolls are     15x - 2y = 4

The vegetarian rolls   20x - 3y = 1


So the values are:

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3 years ago
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if I counted right its 11 they would equal money at 152 dollars

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3 years ago
A large sample of tires from cabs driven within a city have an average tire tread depth of 0.25cm at the end of the winter. If t
frutty [35]

Answer:

0% probability cab tires depths would be shallower than 0.25cm.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2.2, \sigma = 0.33

What is the probability cab tires depths would be shallower than 0.25cm.

This probability is the pvalue of Z when X = 0.25. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.25 - 2.2}{0.33}

Z = -5.9

Z = -5.9 has a pvalue of 0.

0% probability cab tires depths would be shallower than 0.25cm.

7 0
3 years ago
Please Help Me !!!!!!
son4ous [18]
1.\\(4x^2+15x-3)-(-3x^2+5)\\=4x^2+15x-3+3x^2-5\\=7x^2+15x-8\leftarrow A.


2.\\-3f^2+4f-3+8f^2+7f+1\\=5f^2+11f-2\leftarrow C.


3.\\(2x^2+6x+1)+(-7x^2+2x-3)\\=2x^2+6x+1-7x^2+2x-3\\=-5x^2+8x-2\leftarrow B.


4.\\4x^2+3x-3\\\{4;\ 3;-3\}


5.\\6x^4+3x^3-2x^2+15x-14\\\{6;\ 3;-2;\ 15;-14\}\to5\leftarrow A.


6.\\-7x-5x^2+5\\\{-7\}\leftarrow D.


7.\\(2.5\cdot10^4)(4\cdot10^3)=2.5\cdot4\cdot10^{4+3}=10\cdot10^7\\=10^{1+7}=10^8=1\cdot10^8\leftarrow C.


8.\\2^2\cdot2^8=2^{2+8}=2^{10}\leftarrow B.
3 0
3 years ago
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