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den301095 [7]
3 years ago
11

The directory "a" contains its subdirectory "b" and there is no other entry in the directory "a". You want to display "the conte

nts of directory a are: b". The contents are to be displayed using "ls" command. Which command helps you accomplish that?
Computers and Technology
1 answer:
Svet_ta [14]3 years ago
6 0

The answer assumes that the question is about which command help accomplish display directory contents in Unix-like operating systems.

Answer:

The command is <em>ls</em>.

Explanation:

The command <em>ls</em> (short for <em>list</em>) displays a variety of important information in different ways regarding any directory contents. Because of this, it is probably one of the most used commands in Unix-like operating systems.

Any directory can contain directories and files of different sizes, recently created/modified, attributes like permissions for being accessed, and, with this command, we can see all this information by size, chronologically, by owner, and/or by many more ways.  

In the question, we can accomplish to list that the directory "a" contains its sub-directory "b" and no other entry using the next line of code:

Command-line 1: \\ ls\; a (<em>the command "says": display content of a</em>)

Result: b

The result is only the directory <em>b </em>because there is no other entry in it.

To display more information regarding <em>b</em>, we can use the many options available for the command <em>ls</em>, like <em>-a</em> (all entries), <em>-d</em> (only directories), <em>-l</em> (long listing format), and so on, e.g. ls -a  A (display all entries in directory A, included hidden files).

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sineoko [7]

Answer:

// using c++ language

#include "stdafx.h";

#include <iostream>

#include<cmath>

using namespace std;

//start

int main()

{

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 double daily_increase;

 int days;

 double updated_organisms;

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 cout << "Enter the starting number of organisms: ";

 cin >> start_organisms;

 //Validating input data

 while (start_organisms < 2)

 {

     cout << "The starting number of organisms must be at least 2.\n";

     cout << "Enter the starting number of organisms: ";

     cin >> start_organisms;

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 cin>> daily_increase;

 //Validating the increase

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     cout << "The average daily population increase must be a positive value.\n ";

     cout << "Enter the daily population increase: ";

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 while (days<1)

 {

     cout << "The number of days must be at least 1.\n";

     cout << "Enter the number of days: ";

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     updated_organisms = start_organisms + (daily_increase*start_organisms);

     cout << "On day " << i + 1 << " the population size was " << round(updated_organisms)<<"."<<"\n";

     

     start_organisms = updated_organisms;

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}

Explanation:

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Explanation:

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