Answer:
class BST {
static class Node
{
int val;
Node left, right;
}
static boolean checkPerfectBT(Node node, int h, int d)
{
if (node == null)
return true;
if (node.left == null && node.right == null)
{
if(h==d+1)
return true;
else
return false;
}
if (node.left == null || node.right== null)
return false;
return checkPerfectBT(node.left, h, d+1) && checkPerfectBT(node.right, h, d+1);
}
static int height(Node node)
{
int dep = 0;
while (node != null)
{
node = node.right;
dep=dep+1;
}
return dep;
}
static boolean isPerfectBT(Node node)
{
int h = height(node);
return checkPerfectBT(node, h, 0);
}
static Node addNode(int x)
{
Node node = new Node();
node.val= x;
node.right = null;
node.left = null;
return node;
}
public static void main(String args[])
{
int i,j,k;
Node node= null;
node = addNode(34);
node.left = addNode(2);
node.right = addNode(322);
node.left.left = addNode(21);
node.left.right = addNode(23);
node.right.left = addNode(37);
node.right.right = addNode(54);
if (isPerfectBT(node) == true)
System.out.println("This is a Perfect Binary tree");
else
System.out.println("This is Not a perfect Binary Tree");
}
}
Explanation:
- Calculate the depth of BST by using a while loop until it reaches a null value.
- In the addNode method, make an object of Node class.
- In the main method, pass the values to addNode method.
- Finally display the relevant message to show if it's Perfect or not.
