Answer:
The answer is that it is a speaker note.
Explanation:
It leaves a note for people that use presentation files. I use it all the time on my google slides.
Answer:
(A) A web page will not display in a browser unless it passes syntax validation testing.
(C)A web page must pass syntax validation testing before it is used.
Explanation:
A website is a collection of related web pages. A web page is an electronically arranged content page, designed and developed using web development application and language tool and hosted on a web server.
Web page or application development follows a series of well defined stages called software development life cycle (SDLC). The web application must go through these processes from birth to the end-of-life of the application.
The validation testing in SDLC, consisting of unit, acceptance and loading testing, which checks for syntax error or bugs on the written codes, because bugs could slow the loading of the page or even the display and browser compatibility of elements in the code.
The compound condition are:
- 7<12 or 50!=10 is false
- 7<12 and 50<50 is false
- not (8==3) is true
<h3>What is compound condition?</h3>
A compound statement is known to be one that shows up as the body of another statement, e.g. as in if statement.
The compound condition are:
- 7<12 or 50!=10 is false
- 7<12 and 50<50 is false
- not (8==3) is true
Learn more about compound condition from
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Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.