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Anuta_ua [19.1K]
3 years ago
11

X + y = 4 y = 1write in slope intercept form​

Mathematics
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

this is so wrong so 76 89676

Step-by-step explanation:

wrong 95454

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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

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3 0
1 year ago
What are the coordinates of the point? A coordinate grid with a dot placed in the second quadrant. The dot is to the left of pos
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We know that the point is in Q II.  Thus, the x-coordinate of this point will be negative and the y-coordinate will be positive.

The y-coordinate is essentially given, and is y=4.
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The coordinates of the point are (-2, -4).

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4 years ago
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3 years ago
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Where is the opposite of the opposite of -1.9 situated on the number line ​
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Answer:

B

Step-by-step explanation:

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{2x + y = -1}<br> {3x- 5y + -21}
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