$\dfrac{1-\sqrt 5}{1+\sqrt 5}\\\\\\=\dfrac{\left( 1- \sqrt 5\right)\left( 1- \sqrt 5\right)}{\left( 1+ \sqrt 5\right)\left( 1- \sqrt 5\right)}\\\\\\=\dfrac{\left( 1-\sqrt 5)^2}{1^2 - \left(\sqrt 5 \right)^2}\\\\\\=\dfrac{1+\left(\sqrt 5 \right)^2 -2 \sqrt 5\cdot 1}{1-5}\\\\\\=\dfrac{1+5-2\sqrt 5}{-4}\\\\\\=-\dfrac{6-2\sqrt 5}{4}\\\\\\=-\dfrac{2\left(3-\sqrt 5 \right)}{4}\\\\\\=-\dfrac{3-\sqrt 5}{ 2}\\\\\\=\dfrac{\sqrt 5 -3}{2}$

4 0

3 years ago

HELP PLEASE I NEED HELP WITH THIS PROBLEM !!!!!!

scZoUnD [109]

Less than or equal to first equation (solid line)

less tha second equation ( the dotted line)

so its d

3 0

3 years ago

HEEELP ASAP ITS DUE SOON AND ITS TIMED ILL GIVE BRAINLIEST AND LOTS OF POINTS

motikmotik

AnswerdV/dt = 4·pi·(40)2·(-2)

Step-by-step explanation:

8 0

3 years ago

The square prism has a base length of 2 ft. Which describes the cross section of the prism that iS perpendicular to the

Anon25 [30]

Answer:

A-a rectangle with two 12-ft sides and two 2-ft sides

Step-by-step explanation:

Got it right on edge

7 0

3 years ago