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kati45 [8]
3 years ago
15

Place the indicated product in the proper location on the grid. (x + y)(x2 - xy + y2)

Mathematics
2 answers:
mihalych1998 [28]3 years ago
3 0

Answer:

I am truly sorry

Step-by-step explanation:

raketka [301]3 years ago
3 0

Answer:

what grid ... plz show grid for a better answer  

Step-by-step explanation:

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If a fair coin is flipped 15 times, what is the probability that there are more heads than tails?
ludmilkaskok [199]

Answer:

The probability that there are more heads than tails is equal to \dfrac{1}{2}.

Step-by-step explanation:

Since the number of flips is an odd number, there can't be an equal number of heads and tails. In other words, there are either

  • more tails than heads, or,
  • more heads than tails.

Let the event that there are more heads than tails be A. \lnot A (i.e., not A) denotes that there are more tails than heads. Either one of these two cases must happen. As a result, P(A) + P(\lnot A) = 1.

Additionally, since this coin is fair, the probability of getting a head is equal to the probability of getting a tail on each toss. That implies that (for example)

  • the probability of getting 7 heads out of 15 tosses will be the same as
  • the probability of getting 7 tails out of 15 tosses.

Due to this symmetry,

  • the probability of getting more heads than tails (A is true) is equal to
  • the probability of getting more tails than heads (A is not true.)

In other words P(A) = P(\lnot A).

Combining the two equations:

\left\{\begin{aligned}&P(A) + P(\lnot A) = 1 \cr &P(A) = P(\lnot A)\end{aligned}\right.,

P(A) = P(\lnot A) = \dfrac{1}{2}.

In other words, the probability that there are more heads than tails is equal to \dfrac{1}{2}.

This conclusion can be verified using the cumulative probability function for binomial distributions with \dfrac{1}{2} as the probability of success.

\begin{aligned}P(A) =& P(n \ge 8) \cr =& \sum \limits_{i = 8}^{15} {15 \choose i} (0.5)^{i} (0.5)^{15 - i}\cr =& \sum \limits_{i = 8}^{15} {15 \choose i} (0.5)^{15}\cr =& (0.5)^{15} \left({15 \choose 8} + {15 \choose 9} + \cdots + {15 \choose 15}\right) \cr =& (0.5)^{15} \left({15 \choose (15 - 8)} + {15 \choose (15 - 9)} + \cdots + {15 \choose (15 - 15)} \right) \cr =& (0.5)^{15} \left({15 \choose 7} + {15 \choose 6} + \cdots + {15 \choose 0}\right)\end{aligned}

\begin{aligned}\phantom{P(A)} =& \sum \limits_{i = 0}^{7} {15 \choose i} (0.5)^{15}\cr =& P(n \le 7) \cr =& P(\lnot A)\end{aligned}.

6 0
3 years ago
Which is the most accurate way to estimate 25% of 53?
Alex Ar [27]
You can calculate them out and check which one is the most accurate

so if one of the choices was 1/3 of 50, then you would do:
1/3 in the calculator (should be 0.333...) times 50

And you can compare it with the EXACT number, which is:
0.25*53=13.25

This way you can test all the options
8 0
3 years ago
What is the y intercept of this line?<br> y=x-2 <br> PLS SOLVE ASAP!!!
OleMash [197]
-2 is the y intercept
6 0
3 years ago
A cylinder’s volume must be 850 cubic feet while the radius of the cylinder cannot exceed 6 feet. What is the smallest possible
Neporo4naja [7]
I think it's B. not sure though u should wait. till someone else answer to see if I am right
6 0
3 years ago
b) How many white-winged cross bills will there be at the end of June 2020? (Remember that t represent
Mandarinka [93]

Answer:

A dozen = 12

Step-by-step explanation:

I think I’m right

4 0
3 years ago
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