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3 years ago

Place the indicated product in the proper location on the grid. (x + y)(x2 - xy + y2)

Mathematics

2 answers:

mihalych1998 [28]3 years ago

3 0

Answer:

I am truly sorry

Step-by-step explanation:

raketka [301]3 years ago

3 0

Answer:

what grid ... plz show grid for a better answer

Step-by-step explanation:

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A factory packed 9600kg of flour in to small bags and large bags. Each small bag contained 3kg of flour and each large bag conta

yawa3891 [41]

Answer:

696 large bags of flour were packed.

Step-by-step explanation:

Let large bags of flour be 'y'

Let small bags of flour be 'x'. That is x=2040 (according to the question)

$(3 \times x) + (5 \times y) = 9600$

$(3 \times 2040) + ( 5 \times y) = 9600$

$(6120) + (5 \times x) = 9600$

$(5 \times x) = 9600 - 6120$

$(5 \times x) = 3480$

$x = 3480 \div 5$

$x = 696$

HOPE IT HELPS

#PEACE

5 0

3 years ago

Can anyone help me with this?

Iteru [2.4K]

Look at the attached picture ⤴

Hope it will help u ..

3 0

3 years ago

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti

melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that $m = 100, \mu = \frac{1}{100} = 0.01$

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

$P(X > x) = e^{-\mu x}$

This is P(X > 190). So

$P(X > 190) = e^{-0.01*190} = 0.1496$

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

$P(X > x) = 0.08$

$e^{-0.01x} = 0.08$

$\ln{e^{-0.01x}} = \ln{0.08}$

$-0.01x = \ln{0.08}$

$x = -\frac{\ln{0.08}}{0.01}$

$x = 252.6$

Capacity of 252.6 cubic feet per second

5 0

3 years ago

cybil flips a coin and rolls a fair number cube at the same time. What is the probability that she will toss tails and roll a nu

IRISSAK [1]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

Flipping a coin and rolling a number cube are both independent events. Independent events do not rely on the outcome of any previous events. This means that whatever you flip on the coin will have no effect on whatever you roll on the number cube and each flip of the coin or roll of the cube has the same probability as the flip or roll before.

The probability of getting tails on a coin toss is: $\frac{1}{2}$