All categories

3 years ago

I need help on this question

Mathematics

2 answers:

marta [7]3 years ago

6 0

The answer to your question is a 16-gon

Xelga [282]3 years ago

3 0

The name of a 16 sided polygon is 16-gon. heptadecagon is a 17 sided polygon. The other two option don't make sense. I am positive a 16agon and a decahexagon don't exist.

You might be interested in

Mary is going for a walk. She walks 12.5 miles in 5 hours. What is her speed

xz_007 [3.2K]

To find her speed, divide the total distance by the total time:

12.5 miles / 5 hours = 2.5 miles per hour.

3 0

3 years ago

What is heavier a ton of feathers or a ton of elephants

juin [17]

Both weigh the same, 2000 pounds or one ton. You'll just need a lot more feathers than elephants.;

8 0

3 years ago

Read 2 more answers

The Sunday newspaper costs $1.80 per issue delivered and Saturday and weekday papers cost 20 cents per issue delivered. How many

yaroslaw [1]

I think that it's 490 days approximately.

3 0

3 years ago

Read 2 more answers

The roster form of The set of odd natural numbers greater than or equal to 5 and less than or equal to 11 .

Lunna [17]

Answer:

{5, 7, 9, 11}

Step-by-step explanation:

Roster form just means list the elements of the set in the brackets.

It says the elements are greater than or equal to five and less than or equal to 11. So we start at 5 and end at 11.

We list {5, 7, 9, 11} because these elements follow the rule that they must be odd natural numbers. Natural numbers are the numbers you can count starting from 0 like {0, 1, 2, 3, ...}.

4 0

3 years ago

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)

$P(A)P(B^{c}) + P(A^{c})P(B)=$ (because of independence)

= (0.87)(0.16) + (0.13)(0.84) = 0.2484

P(X = 2) = P(both components meet specifications) =

$P(A\cap B) = P(A)P(B)$ (because of independence)

= (0.87)(0.84)

= 0.7308

8 0

3 years ago