14 miles Substitute AB = 3 and BC = 11 in above equation.
Slope of the line = 
.
y-intercept of the line = -7.
Solution:
General form of equation of a line:
y = mx + c
where m is the slope and c is the y-intercept of the line.
Equation of a line:
To compare this with general equation.
Slope of the line = .
y-intercept of the line = -7.
I have to admit I don't know what exactly you are asking, but I think this is it: 10m/s.
Divide m/s by time.
Hello! I'll write the instructions to graph these functions.
f(x)=x
Technically, this function is y=x, so the slope would be 1. To graph this one, start at the origin (0,0) and move up one unit, and to the right one unit since this is a positive slope.
g(x)= -1/3x+2
First, plot a point at y=2 when x=0. 2 is your y-intercept. Your slope is negative, so the line will be decreasing. From your first point, head down 1 unit and to the right 3 units. Continue plotting points from the previous points.
Also, if you have a graphing calculator, here are the steps to graphing the functions: ON, Y= (enter your functions), and press GRAPH or 2nd, TABLE to see individual points. Hope this helps! :)
if the diameter is 20, the its radius must be half that or 10.
![\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ A=5\pi \\ r=10 \end{cases}\implies \begin{array}{llll} 5\pi =\cfrac{\theta \pi (10)^2}{360}\implies 5\pi =\cfrac{5\pi \theta }{18} \\\\\\ \cfrac{5\pi }{5\pi }=\cfrac{\theta }{18}\implies 1=\cfrac{\theta }{18}\implies 18=\theta \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20sector%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20r%5E2%7D%7B360%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3D%5Cstackrel%7Bdegrees%7D%7Bangle%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20A%3D5%5Cpi%20%5C%5C%20r%3D10%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%205%5Cpi%20%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20%2810%29%5E2%7D%7B360%7D%5Cimplies%205%5Cpi%20%3D%5Ccfrac%7B5%5Cpi%20%5Ctheta%20%7D%7B18%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B5%5Cpi%20%7D%7B5%5Cpi%20%7D%3D%5Ccfrac%7B%5Ctheta%20%7D%7B18%7D%5Cimplies%201%3D%5Ccfrac%7B%5Ctheta%20%7D%7B18%7D%5Cimplies%2018%3D%5Ctheta%20%5Cend%7Barray%7D)
