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malfutka [58]
3 years ago
5

E=VIT how would I isolate the “V” variable

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer:

V =\frac{E}{IT}

Step-by-step explanation:

You can isolate the "V" variable by dividing by IT on both sides:

\frac{E}{IT} =\frac{VIT}{IT}

On the left, the IT from the top and bottom cancel, leaving you with just V:

V =\frac{E}{IT}

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If g(x)=x^2-5x+8, find g(8)
ycow [4]

Answer:

Option A) 32

Step-by-step explanation:

Given the quadratic function, g(x) = x²- 5x + 8:

In order to evaluate and determine the output value given g(8), substitute the input value into the function:

g(x) = x²- 5x + 8

g(8) = (8)²- 5(8) + 8

g(8) = 64 - 40 + 8

g(8) = 32

Therefore, the correct answer is Option A) 32.

5 0
3 years ago
How to write eight ten-thousandths of thirty-five million in scientific notation?
VashaNatasha [74]
Eight ten-thousandths = 8*(1/10,000) = 8/10⁴ = 8 x 10⁻⁴.
Thirty-five million = 35*(1,000,000) = 35 x 10⁶

Therefore eight ten-thousandths of thirty-five million is
(8 x 10⁻⁴) * (35 x 10⁶)
= 280 x 10⁶⁻⁴
= 280 x 10²
= (2.8 x 10²) * 10²
= 2.8 x 10⁴

Answer:  2.8 x 10⁴
5 0
4 years ago
which is the solutions to the system of equations shown { 3x - y = 6 and here is the other equation{ x - 2y = -18
Vinvika [58]

Answer:

(6, 12)

Step-by-step explanation:

{ 3x - y = 6

{ x - 2y = -18

by using elimination:

6x -2y=12

x - 2y= -18

________-

5x = 30

x = 6

y = 18-6 = 12

the solutions = {(6, 12)}

3 0
3 years ago
KLMNO is a regular pentagon and length of MN is 4 inches. What is
soldier1979 [14.2K]

Answer:

4in?

Step-by-step explanation:

all sides of a Pentagon are equal. so if one side is 4in, the others should also be 4in...

8 0
3 years ago
In a certain game of chance, your chances of winning are 0.2. Assume outcomes are independent and that you will play the game fi
IRINA_888 [86]

Answer:

73.73% probability that you win at most once

Step-by-step explanation:

For each game that you play, there are only two possible outcomes. Either you win, or you lose. The games are independent from each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In a certain game of chance, your chances of winning are 0.2.

This means that p = 0.2

Assume outcomes are independent and that you will play the game five times.

This means that n = 5

What is the probability that you win at most once

P(X \leq 1) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.2)^{0}.(0.8)^{5} = 0.3277

P(X = 1) = C_{5,1}.(0.2)^{1}.(0.8)^{4} = 0.4096

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.3277 + 0.4096 = 0.7373

73.73% probability that you win at most once

5 0
3 years ago
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