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malfutka [58]
3 years ago
5

E=VIT how would I isolate the “V” variable

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer:

V =\frac{E}{IT}

Step-by-step explanation:

You can isolate the "V" variable by dividing by IT on both sides:

\frac{E}{IT} =\frac{VIT}{IT}

On the left, the IT from the top and bottom cancel, leaving you with just V:

V =\frac{E}{IT}

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Need help on #30 and 31 thanks!!
Nina [5.8K]
30)

\bf \begin{array}{llll}
y=&{{ a}}x^2&{{ +b}}x&{{ +c}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}

31)


a simple case for that would just be, using an equation with an imaginary value, let's do so

\bf \sqrt{-5}=x\implies \sqrt{-1\cdot 5}=x\implies \sqrt{-1}\sqrt{5}=x\implies i\sqrt{5}=x\\\\
-------------------------------\\\\
\textit{so, we'll use that imaginary value then}\\\\
\sqrt{-5}=x\implies -5=x^2\implies 0=x^2+5\implies \boxed{y=x^2+5}

when you get a "solution" or zero with an "i" or an imaginary value, is just a way to say, there's really no solution, the function never touches the x-axis
3 0
3 years ago
Can someone help please i don't understand ​
mel-nik [20]

Answer:

x= -3/11

Step-by-step explanation:

Use cross multiplication:

5(x+1)= -1(6x-2)

Simplify:

5x+5= -6x+2

Subtract 5 from both sides:

5x= -6x-3

Add 6x to both sides:

11x= -3

Divide both sides by 11:

x= -3/11

Hope this helps ^-^

3 0
3 years ago
I need help plsss<br> Nowww
enyata [817]
8: tenths
9:hundredth
7:thousandth
8 0
3 years ago
Please help!!!!!!!!!!!!!!!!!! -3x+2 less than 8
sleet_krkn [62]
-3x+2 < 8
-2 -2
-3 /-3x <6/-3
x >-2

So x>-2
7 0
3 years ago
How is the product of 2 and -5 shown on a number line
otez555 [7]

Answer: on point -10

Step-by-step explanation:

Because 2*-5 is -10.

8 0
2 years ago
Read 2 more answers
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