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Korvikt [17]
3 years ago
13

Markus scared 85, 92, 82, and 94 on the first four tests of the semester. His teacher has not yet told him his score on his fift

h test, but did tell him that his score on the fifth test is five points lower than the average (arithmetic mean) of all five tests. Which equation could Markus use to determine the score of the fifth test, x?
Mathematics
2 answers:
vovikov84 [41]3 years ago
5 0

Answer:

5(x + 5) = 353 + x

Step-by-step explanation:

i got it right on edge

alexandr1967 [171]3 years ago
3 0

Answer:

y — x = 5

5y — x = 353

Step-by-step explanation:

Let the fifth score be x

Let the average of all the scores be y.

But the fifth score is 5 points lower than the average ie

y — x = 5 (1)

The average of the scores is the sum of all the scores divided the number of scores. This is written as

y = (85 + 92 + 82 + 94 + x) /5

y = (353 + x) /5

Multiply through by 5

5y = 353 + x

Rearrange the equation

5y — x = 353 (2)

The equation Markus will use to determine the x is given as

y — x = 5

5y — x = 353

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Answer:

-16x-28

Step-by-step explanation:

Break it into little pieces; start with distributing the -7:

-7(5+x)

-35-7x

Now add the rest of the problem: 7-35-7x-9x

Combine like terms: 7-35               7x-9x

7-35=-28             7x-9x=-16x

Rearrange so the coefficient and variable are upfront, giving you:

-16x-28

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In a public show 75 % of seats were filled if there were 600 seats in the hall, how many seats were vacant ?
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The table below shows data from a survey about the amount of time students spend doing homework each week. The students were in
nadezda [96]

Answer:

The correct option is;

Both spreads are best described by the standard deviation

Step-by-step explanation:

The given information are;

,                                    College                       High School

High,                              20                               20

Low,                                6                                 3

Q₁,                                   8                                 5.5

Q₃,                                  18                                16

IQR,                                 10                                10.5

Median,                           14                                11

Mean,                              13.3                             11

σ,                                      5.2                             5.4

Checking for outliers, we have

College

Q₁ - 1.5×IQR gives 8 - 1.5×10 = -7

Q₃ + 1.5×IQR gives 18 + 1.5×10 = 33

For high school

Q₁ - 1.5×IQR gives 5.5 - 1.5×10.5 = -10.25

Q₃ + 1.5×IQR gives 16 + 1.5×10.5 = 31.75

Therefore, there are no outliers and the data is representative of the population

From the data, for the college students, it is observed that the difference between the mean, 13.3 and Q₁, 8, and between Q₃, 18 and the mean,13.3 is approximately the standard deviation, σ, 5.2

The difference between the low and the high is also approximately 3 standard deviations

Therefore the college spread is best described by the standard deviation

Similarly for the high school students, the IQR is approximately two standard deviations, the  difference between the mean, 11 and Q₁, 5.5, and between Q₃, 16 and the mean,11 is approximately the standard deviation, σ, 5.4

Therefore the high school spread is also best described by the standard deviation.

4 0
3 years ago
TONTE UI E doove
vagabundo [1.1K]

pretty sure its growth

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