Step-by-step explanation:
Given,
y=2x=,z=3x,r=4x
Now,
x+y+z+r=360°(complete turn)
x+2x+3x+4x=360°(given)
10x=360°
x=360°/10
x=36°
Hence,
x=36°
y=2x=2×36°=72°
z=3x=3×36°=108°
r=4x=4×36°=144°
Hello! And thank you for your question!
Use Pemdas to get
3^(n+2)*4=3^28
Rewrite the equation:
3^4(n+2) = 3^28
Cancel the base of 3:
4(n + 2) = 28
Then divide 4 on both sides:
2 + n = 28/4
Simplify 28/4:
2 + n = 7
Subtract 2 on both sides:
n = 7 - 2
Finally simplify 7 - 2:
n = 5
Final Answer:
n = 5
I assume that this 'something' has a rectangular shape. If its width is 5m, than the length of two sides is 2 * 5 = 10m. Now if the perimeter is 22 square meters, then the lenght of another two sides is 12 / 2 = 6.
12 because 22 (the perimeter) - 10 (lenght of the 2 sides) = 12 (length of another 2 sides).
Answer:
Step-by-step explanation:
4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.
b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.
c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.
d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.
e). If a parallelogram has four congruent sides, then it must be a SQUARE.
5). Given quadrilateral SELF is a rhombus.
a). All sides of a rhombus are equal,
Therefore, ES = EL = 25
b). Diagonals of a rhombus bisects the opposite angles,
Therefore, m∠ELS = m∠FLS
3x - 2 = 2x + 7
3x - 2x = 7 + 2
x = 9
c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.
m∠ELF = 2(m∠ELS) = 2(2y - 9)
m∠LES = 2(m∠LEF) = 2(3y + 9)
And 2(2y - 9) + 2(3y + 9) = 180
(2y - 9) + (3y + 9) = 90
5y = 90
y = 18
Answer:
A =First term of the pattern = 11
To find the first five terms we have to use the rule which is
Add 10 to first term and then subtract 5 from it.Which is equivalent to
= A +10 -5
1. Second Term = 11 + 10 -5
= 21 - 5
=16
→Third term = 16 +10-5
= 26 - 5
= 21
→Fourth term : 21 + 10 - 5
= 31 -5
= 26
→Fifth term : 26 +10 -5
= 36- 5
= 31
→Sixth term:
=31 + 10- 5
= 41 -5
= 36
So, the first five term apart from 11 is 16, 21,26,31,36 which is an Airthmetic progression.
