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djyliett [7]
3 years ago
7

You learned that properly edited resumes are necessary for making a good impression on a university or a potential employer. Dis

cuss the consequences of submitting a poorly edited and formatted resume while looking for a job or pursuing higher studies.
Computers and Technology
2 answers:
I am Lyosha [343]3 years ago
7 0

Answer: Something poorly edited or revised can look bad to employers or colleges. It shows that you either rushed or didn’t give enough thought to the work you did. On the other hand, submitting something well polished looks great to business hiring and colleges looking for their next top scholars.

Explanation: PLATO

beks73 [17]3 years ago
5 0

Answer:

Resume is the important document for job seekers. As much as the resume is better, there is more chance to grab the job.

If the resume is poor, the employer may not call you for the interview.

Explanation:

Resume is the document that create and impression over the potential employer or university.

If someone have very good hard and soft skills, and does not mention all the skills in resume, then employer could not that skills that you may have. Because your resume is the document that represent you when you are not in front of the employer.  This is the first document, presented that, what  you are and how you are beneficial for the company.

<em>If your resume is poor it may cause that He cannot call you for the interview or not considered for that JOB.</em>

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g Write a program that prompts the user for an integer n between 1 and 100. If the number is outside the range, it prints an err
grin007 [14]

Answer:

The cpp program is given below.

#include<iostream>

#include<iomanip>

using namespace std;

int main() {

   

   // variables declared

   int n;

   int sum=0;

   float avg;

   

   do

   {

       // user input taken for number    

       cout<< "Enter a number between 1 and 100 (inclusive): ";

       cin>>n;

       

       if(n<1 || n>100)

           cout<<" Number is out of range. Enter valid number."<<endl;

       

   }while(n<1 || n>100);

   

   cout<<" "<<endl;

   

   // printing even numbers between num and 50  

   for(int num=1; num<=n; num++)

   {

       sum = sum + num;

   }

   

   avg = sum/n;

   

   // displaying sum and average

   cout<<"Sum of numbers between 1 and "<<n<<" is "<<sum<<endl;

   cout<<"Average of numbers between 1 and "<<n<<" is ";

   printf("%.2f", avg);

   

       return 0;

}

OUTPUT

Enter a number between 1 and 100 (inclusive): 123

Number is out of range. Enter valid number.

Enter a number between 1 and 100 (inclusive): 56

 

Sum of numbers between 1 and 56 is 1596

Average of numbers between 1 and 56 is 28.00

Explanation:

The program is explained below.

1. Two integer variables are declared to hold the number, n, and to hold the sum of numbers from 1 to n, sum. The variable sum is initialized to 0.

2. One float variable, avg, is declared to hold average of numbers from 1 to n.

3. User input is taken for n inside do-while loop. The loop executes till user enters value between 1 and 100. Otherwise, error message is printed.

4. The for loop executes over variable num, which runs from 1 to user-entered value of n.

5. Inside for loop, all the values of num are added to sum.

sum = sum + num;

6. Outside for loop, average is computed and stored in avg.

avg = sum/n;

7. The average is printed with two numbers after decimal using the following code.

printf("%.2f", avg);

8. The program ends with return statement.

9. All the code is written inside main() and no classes are involved.

3 0
3 years ago
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